Answer:
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Probability that a randomly selected adult has an IQ greater than 123.4.
This is 1 subtracted by the pvalue of Z when X = 123.4. So



has a pvalue of 0.9595
1 - 0.9595 = 0.0405
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
<span><span> combine like terms4ln(x) = 8
</span><span>divide both sides by 4.ln(x) = 2
</span><span>exponentiate both sides.<span>eln(x) = e^2</span>
</span><span>inverse property of exponents and logs <span>x = e^<span>2
pls return favor and answer question in profile pls
</span></span></span></span>
The next step is to draw an arc with center E.
Answer:

Step-by-step explanation:
Given:


We have to find the value of 'h'
So, putting the given values in the equation to find the value of 'h'.

Implementing the given values in the given equations:

So, the value of 'h' is
