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vodomira [7]
3 years ago
13

What is 8 4/9 as a decimal?

Mathematics
2 answers:
ale4655 [162]3 years ago
6 0

8.4 or it can be 8.44444444

torisob [31]3 years ago
3 0
8.4444 i think I’m not sure
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Find the solutions of the equation 3x = x4, rounded to two decimal places. (Enter your answers as a comma-separated list.)
Rzqust [24]

Answer:-0.802; \ 1.517

Step-by-step explanation:

Given

3^x=x^4

Here, two functions are given that is y=3^x and y=x^4

Check for the intersection of the graph of two curves

From the graph, they cut at two different points  i.e. x=-0.802\ \text{and}\ x=1.517

Rest two roots are negative.

6 0
3 years ago
twice a number,n, subtracted form 36 is less than 15 more than one third the number. Find all possible values for the number. SH
garri49 [273]
Twice (2 x ) a number (n), subtracted (-) from 36, is less than (<) 15 more than (+) one-third (1/3) the number (n).

36 - 2n < 15 + 1/3n   Subtract 15 from both sides
21 - 2n < 1/3n           Add 2n to both sides
       21 < 7/3n           Multiply both sides by 3/7 to cancel out the fraction
    63/7 < n                Simplify the fraction
         9 < n                Switch the sides to make it easier to read
         n > 9

The possible values for the number are anything over 9.


4 0
3 years ago
Suppose ST¯¯¯¯¯¯ has one endpoint at S(0, 0). What are the coordinates of T if (4, 5) is 1/3 of the way from S to T? ( , )
makvit [3.9K]

Answer:

coordinates are (8,10)

Step-by-step explanation:

7 0
3 years ago
Find the inverse of the function f(x) = 7x-6
solmaris [256]

Answer: f −1 (X) = x/7 +6/7

5 0
3 years ago
Solve the equation for X.
OlgaM077 [116]

Answer:

\large\boxed{\left[\begin{array}{ccc}10&-30\\-10&-2\end{array}\right]}

Step-by-step explanation:

X-3\left[\begin{array}{ccc}2&-8\\-4&2\end{array}\right] =\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]\\\\X-\left[\begin{array}{ccc}(3)(2)&(3)(-8)\\(3)(-4)&(3)(2)\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]\\\\X-\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]

X-\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]+\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]+\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]\\\\X=\left[\begin{array}{ccc}4+6&(-6)+(-24)\\2+(-12)&-8+6\end{array}\right]\\\\X=\left[\begin{array}{ccc}10&-30\\-10&-2\end{array}\right]

7 0
3 years ago
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