Will give brainliest for right answer

A Christmas gift is tied with ribbon the bow requires 47cm of ribbon, what is the total length of the ribbon in cm?

Sophie [7]

The complete question is as follows: A Christmas gift is tied with ribbon the bow requires 47cm of ribbon, what is the total length of the ribbon in cm?

Answer: The total length of the ribbon is 177 cm.

Step-by-step explanation:

As there are 4 sides of the rectangular box and 20 cm of ribbon is on each side. This means that a total of $4 \times 20 cm$ = 80 cm is there on the top and bottom.

Hence, length of ribbon attached at the left and right side of the box is as follows.

$2.5 \times 10 cm = 25 cm\\2 \times 25 cm = 50 cm$

This means that on both left and right side a total of 50 cm is there.

Therefore, total length of ribbon is as follows.

Total length = 47 cm + 50 cm + 80 cm = 177 cm

Thus, we can conclude that the total length of the ribbon is 177 cm.

7 0

3 years ago

F(x)=x^3+7x-20; a= -5, b= -3

Ede4ka [16]

Answer: a is actually 1 and b is 7

Step-by-step explanation:

this is a quadratic formula and a is the leading coefficient which is 1 and 7 is b

3 0

3 years ago

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg. How many toys did

Vilka [71]

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.

Let the number of toys Oleg has = x

Let the number of toys Sasha has = y

Let the number of toys Dima has = z

Sasha had twice as many toys as Oleg

So y = 2*x= 2x

Dima had 40 more toys than Oleg.

z = x + 40

Oleg, Sasha, and Dima shared 600 toys

x + y + z= 600

We know y=2x and z=x+40

Replace it for y and z

$x + y + z = 600$

$x + 2x + x + 40 = 600$

$4x + 40 = 600$

Subtract 40 on both sides

$4x = 600 - 40$

Divide by 4 on both sides

$x = \frac{560}{4} = 140$

Oleg had 140 toys

4 0

4 years ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$

$\Rightarrow x =(50 \times 14)/57=12.28$ grams

and $y = 14-x= 14-12.28=1.72$ grams.

Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.

3 0

3 years ago

What is the real part of 4-5i a. 5 b. 4 c. -5i d. -5 PLEASE HELP!

marysya [2.9K]

Answer:

Step-by-step explanation:

A complex number in its rectangular form is expressed as x+iy where x is the real part of the complex number and y is the imaginary because it is attached to the imaginary number i.

Given the complex number 4-5i, comparing the complex number with x+iy

4 = x and iy = -5i

Hence x = 4 and y = -5.

Since x is the real part of the complex number x+iy, hence 4 will be the real part of the complex number 4-5i based on comparison.

7 0

4 years ago