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Leona [35]
2 years ago
15

Find the output, k, when the input, T. iS 5. 67 + 100

Mathematics
1 answer:
rjkz [21]2 years ago
3 0

Answer:

70

Step-by-step explanation:

k = 6(-5)+100 = -30+100 = 70

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10+2(x - 7) - 4+3(x+6) - 1 (distributive property)
Alja [10]
I got 5x-9 as the answer
6 0
3 years ago
NEED HELP FAST CLICK TO SEE PLS
ss7ja [257]

Answer:

Last Option

Step-by-step explanation:

Last one because the dot on top of the 4 is filled in and that means it can also equal 4. The rest of the line is going to the right of the 4 so x will be more than 4. The little line below the more than sign means it can also equal 4. Hope this helped :)

4 0
3 years ago
Read 2 more answers
What is the equation that represents the scenario?
miskamm [114]

Answer:y=5x

Step-by-step explanation:

B

7 0
3 years ago
How many terms are in the following sequence? 131072, ..., 8, 4, 2
Klio2033 [76]

Answer:

  17 terms

Step-by-step explanation:

131072 = 2^17

8 = 2^3

4 = 2^2

2 = 2^1

Apparently, the sequence is powers of 2 from 17 down to 1, so there are 17 terms in the sequence.

8 0
3 years ago
Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am
zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

So we are looking for the time

Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

8 0
1 year ago
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