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iVinArrow [24]
3 years ago
14

What is the equation for the line in slope intercept form plz help ASAP

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

<em>y = - 4x + 5 </em>

Step-by-step explanation:

y = mx + b

(0, b) y-intercept

m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

~~~~~~~~~~

( - 2, 13)

(0, <em>5</em>) <----- y-intercept

(3, - 7)

(4, - 11)

<em>m =</em> \frac{-11+7}{4-3} = <em>- 4</em>

<em>y = - 4x + 5</em>

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4 0
2 years ago
Read 2 more answers
Please show me how to do this.
Aloiza [94]

Answer:

f(x) = \dfrac{1}{2}(x - \ln (x - 1) - 2)

Step-by-step explanation:

f'(x) = \dfrac{1}{2} - \dfrac{1}{2x - 2}

f(x) = \int (\dfrac{1}{2} - \dfrac{1}{2x - 2}) dx

f(x) = \int [\dfrac{1}{2} - \dfrac{1}{2(x - 2)}] dx

f(x) = \int \dfrac{1}{2}dx - \dfrac{1}{2} \int \dfrac{1}{x - 1} dx

f(x) = \dfrac{1}{2}x - \dfrac{1}{2} \ln (x - 1) + C

f(x) = \dfrac{x - \ln (x - 1)}{2} + C

f(2) = \dfrac{2 - \ln (2 - 1)}{2} + C = 0

f(2) = \dfrac{2 - \ln (1)}{2} + C = 0

f(2) = \dfrac{2}{2} + C = 0

f(2) = 1 + C = 0

C = -1

f(x) = \dfrac{x - \ln (x - 1)}{2} - 1

f(x) = \dfrac{1}{2}[x - \ln (x - 1) - 2]



7 0
3 years ago
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