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2 years ago

How do you find the distance of two points on a graph

Mathematics

2 answers:

krek1111 [17]2 years ago

8 0

By using the distance formula

dem82 [27]2 years ago

3 0

Answer: you use the distance formula

Step-by-step explanation:

d = distance

(x_1, y_1) = coordinates of the first point

(x_2, y_2) =coordinates of the second point

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What is 33 1/3% as a decimal? NOW!!!

Anna35 [415]

Answer:

0.333333 repeating

Step-by-step explanation:

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2 years ago

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If tan(A+B)=8 and tan B = 1/57 find tan A <br> Plz show work

Degger [83]

Answer:A=8-1/57=455/57=7.98

Step-by-step explanation:

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2 years ago

Is the given number a solution of the equation?<br> 8=2+3; 10

kykrilka [37]

Answer:

No.

Step-by-step explanation:

8 doesn't equal 0 on the very right, which means it's not a solution to the equation. So therefore, it is false based on the equation.

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2 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

3 years ago

The owners of an industrial plant want to determine which of two types of fuel (gas or electricity) will produce more useful ene

madreJ [45]

Answer:

d. H0: $(\mu_e - \mu_g) = 0$ vs. $Ha: (\mu_e - \mu_g) \neq 0$

Step-by-step explanation:

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

On this case the Management try to determine if there is a difference in the average investment/quad between using electricity and using gas. So this needs to be on the alternative hypothesis. And the complement of the alternative hypothesis would be on the null hypothesis.

Null hypothesis : $\mu_e = \mu_g$

Alternative hypothesis: $\mu_e \neq \mu_g$

Or equivalently:

Null hypothesis : $\mu_e - \mu_g = 0$

Alternative hypothesis: $\mu_e - \mu_g \neq 0$

Other important thing is that on the alternative hypothesis we never can have the symbol equal.

So on this case the best options is:

d. H0: $(\mu_e - \mu_g) = 0$ vs. $Ha: (\mu_e - \mu_g) \neq 0$

7 0

3 years ago