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4 years ago

2 m 2 in 1.7 m 3 m 1 m 1 m

Mathematics

2 answers:

eimsori [14]4 years ago

7 0

21.4 I think butt im not an expert

lana66690 [7]4 years ago

3 0

21.4

it’s an equal triangle so you do
2 x 3 = 6
6 x 3 = 18
2(1 x 1.7) = 3.4
18 + 3.4 = 21.4

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Rickey has been commissioned to paint a mural that is allowed to have an area of 50 square meters. To make the rectangle shape o

Leno4ka [110]

Answer:

12.808 meter is the length should Rickey use for the mural.

Step-by-step explanation:

Area of the mural = A = $50 m^2$

Length of the mural = l

Width of the mural = w

l = 5 + 2w

Area of the rectangle = l × w

$A=(5+2w)\times w$

$50 m^2=5w+2w^2$

$2w^2+5w-50=0$

Solving above equation with the help of Completing squares method:

$(\sqrt{2}w)^2+2\times \sqrt{2}w\times \frac{5}{2\sqrt{2}}+(\frac{5}{2\sqrt{2}})^2-50=(\frac{5}{2\sqrt{2}})^2$

$(a+b)^2=a^2+b^2+2ab$

$(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=(\frac{5}{2\sqrt{2}})^2+50$

$(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=\frac{25}{8}+50$

$(\sqrt{2}w+\frac{5}{2\sqrt{2}})^2=\frac{425}{8}$

$(\sqrt{2}w+\frac{5}{2\sqrt{2}})=\pm\sqrt{\frac{425}{8}}$

w = 3.904 m (accept)

w = -6.404 m (reject)

l = (5 + 2w)m = 5 + 2 × (3.904) m= 12.808 m

12.808 meter is the length should Rickey use for the mural.

3 0

3 years ago

Write the equation of a line, in slope-intercept form, that has a slope of m=6 and passes through the point (3, 11) . Enter your

sp2606 [1]

Answer:

Step-by-step explanation:

y - 11 = 6(x - 3)

y - 11 = 6x - 18

y = 6x - 7

4 0

3 years ago

Use the formula below to find the value of $1300 invested at 4.2% interest compounded continuously for 5 years 9 months. Round y

iren2701 [21]

Hi there

The formula of compounded continuously is
A=pe^rt
A future value?
P present value 1300
E constant
R interest rate 0.042
T time 5years+9/12=5+9/12=5.75years
So
A=1,300×e^(0.042×5.75)
A=1,655.10 round your answer to get
A=1655

Good luck!

3 0

3 years ago

A man runs to a telephone and back in 15 minutes. His speed on the way to the telephone is 5m/s and his speed on the way back is

xz_007 [3.2K]

This is a distance problem so we can use distance = rate x time.

Given: the distance to the telephone is the same as the distance back from the telephone. We also know the two speeds and the total time for the trip.

But first let's convert 15 minutes into seconds: 15*60 = 900 seconds.

So: d = 5(t1) (t1 is the time he took to run to the telephone)
d = 4(t2) (t2 is the time he took to come back from the telephone
t1 + t2 = 900 or t1 = 900 - t2

Now use substitution:

5t1 = 4t2
5*(900 - t2) = 4t2
4500 - 5t2 = 4t2
4500 = 9t2
500 = t2
So therefore t1 = 400

So the distance to the telephone is 5*400 = 2000 meters

5 0

4 years ago

Write an equation to represent the measures of the angles.

Rus_ich [418]

The angle x and the angle 18 degrees combine to form a right angle. The two angles add to 90 degrees

If you want to solve for x, then subtract 18 from both sides

x+18 = 90

x+18-18 = 90-18

5 0

3 years ago