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kherson [118]
2 years ago
6

Answer fast! Will mark brainliest-- Reflect quadrilateral SQRT over the y-axis. Then translate the new quadrilateral 3 units to

the right. What are the coordinates of the vertices of the final image?
A. S’(-2, 3), Q’(1, 2), R’(-3, -2), T’(-3, 1)
B. S’ (0, 1), Q’(1, -5), R’(7, -4), T’(6, -1)
C. S’(8, 3), Q’(5, 2), R’(6, -2), T’(9, -1)
D. S’(5, 3), Q’(2, 2), R’(3, -2), T’(9, -1)
Mathematics
2 answers:
Veronika [31]2 years ago
8 0

Answer:

D).S’(5, 3), Q’(2, 2), R’(3, -2), T’(9, -1) should be the correct answer.

Step-by-step explanation:

I took the test on edg.

Usimov [2.4K]2 years ago
5 0

Answer:

i think the answer for the new coordinates is C but it doesnt make sence

Step-by-step explanation:

i cant tell for sure because their isnt a picture of where the quadrilaterel is im sorry

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Ok, now if we know that the vertices of the trapezoid are:

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And we move the whole figure 4 units to the right, then all the vertices are moved 4 units to the right.

Then the new vertices of the figure will be:

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Then the coordinates of the image of the trapezoid (of the new vertices) are:

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