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3 years ago

Can a triangle be drawn with the following side lengths? Why or why not? 2 cm, 11 cm, 8 cm

Mathematics

2 answers:

guajiro [1.7K]3 years ago

4 0

the sum of the 2 smaller should be bigger than 11

2+8=10

10 is not bigger than 11

aniked [119]3 years ago

4 0

No, The third important property of triangles is the triangle inequality rule, which states: the length of a side of a triangle is less than the sum of the lengths of the other two sides and greater than the difference of the lengths of the other two sides.

For example:

2+8=10 which is not a larger number than 11.

This is a very important rule to making triangles.

Plz giv me branliest

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What you get if you answer this! Brainly, 20 points, thanks thats all please answer it

Maslowich

Answer:

h = 8

Let the unknown number be h for height

V = LWH

984 = 20.5 x 6 x h

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3 years ago

Hi Can you please help me

dimaraw [331]

Answer:

x = 68°

Explanation:

given ∠CBE = 22°
∠ABD is parallel to ∠CBE, thus has same angle of 22°
∠ADB is right angle and thus has 90° angle.
total sum of interior angles in triangle is 180°

We can find x by:

x + 90° + 22° = 180°

x + 112° = 180°

x = 180°- 112°

x = 68°

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2 years ago

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Which answer correctly estimates the product of 3.09 × 304.87? A. about 9.0 B. about 9.9 C. about 90 D. about 900

KiRa [710]

The answer is D) About 900

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3 years ago

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Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

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The quotient of 4/7 is a decimal number. How many digits in the quotient are overlined?

Bas_tet [7]

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