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loris [4]
3 years ago
15

Now find the difference what is 2/3 - 3/5

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

1/5

Step-by-step explanation:

subtract 2/3 and 3/5

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4 years ago
6 divided by 20 write your answer in a decimal form
Kobotan [32]

Answer:

0.3

Step-by-step explanation:

I just need 20 characters so yeah

6 0
2 years ago
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The angles of a triangle are in a ratio 1:3:8. What are the angles?<br>​
xxTIMURxx [149]

Answer:

15° , 45°, 120°

Step-by-step explanation:

sum the parts of the ratio, 1 + 3 + 8 = 12 parts

the sum of the 3 angles in a triangle = 180° , then

180° ÷ 12 = 15° ← value of 1 part of the ratio, then

3 parts = 3 × 15° = 45°

8 parts = 8 × 15° = 120°

the 3 angles are 15° , 45° , 120°

6 0
3 years ago
The length of bills backyard swimming pool is 60 feet longer than the width of the pool. The surface area of the water is 1600 s
shutvik [7]

Answer:

The width is 20 ft and the length is 80 ft

Step-by-step explanation:

Area = l * w

l = w +60

SA = 1600 ft^2 ( which is the regular area)  The surface area of the water is just what is on top  which is length times width

1600 = l*w

Substitute in l = w+60

  1600       = (w+60) *w

Distribute the w

1600 = w^2 +60w

Subtract 1600 from each side

1600-1600 = w^2 + 60w -1600

0 =  w^2 + 60w -1600

Factor

0=(w-20) (w+80)

Using the zero product property

w-20=0   w+80 =0

w=20  or w=-80

The width cannot be negative   so

w=20

Now we need to find the length

l = w+60

l = 60+20

l =80

7 0
3 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
2 years ago
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