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Ket [755]
3 years ago
7

Which equation represents a proportional relationship? A. y=x/8. B. y=8/x. C. y=x/8+8. D. y=8/x+8.

Mathematics
1 answer:
Ann [662]3 years ago
6 0

Answer:

c and d have a proportial relationship.

Step-by-step explanation:

hope this helps

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the total cost of 4 pens and 7 mechanical pencils is $13.25 the cost of each pencil is $0.75 write an equation that could be use
balu736 [363]
4x+7y=$13.25
4x+ 7($0.75)
7 0
3 years ago
7. Solve the proportion
RideAnS [48]

Answer:

14

Step-by-step explanation:

56 divided by 7 = 8

14 divided by 7 = 2

hinting at 8/2

4 0
4 years ago
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PLEASE HELP<br><br> Graph the ordered pairs for y = 3x + 3 using r = {-2, 1, 2}.
Fed [463]

9514 1404 393

Answer:

  (-2, -3), (1, 6), (2, 9) are plotted in the attached graph

Step-by-step explanation:

For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).

For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).

For x = 2, y = 3(2) +3 = 9. The ordered pair is (2, 9).

The graph is attached.

5 0
3 years ago
Read 2 more answers
Solve the equation for a.
katrin [286]

Answer:

a= \frac{k}{9b+4}

Step-by-step explanation:

In this question, you would solve for "a".

Solve:

K = 4a + 9ab

Since we have our "a" on the same side, we can factor it out from the variables:

K = a(9b + 4)

To get "a" by itself, we would have to divide both sides by 9b + 4:

K/9b+ 4 = a

Your answer would be K/9b+ 4 = a

It would look like this: a= \frac{k}{9b+4}

8 0
3 years ago
Read 2 more answers
Is the binomial a factor of the polynomial nominal function?
Sedbober [7]

The factors for given equation f(x)=x^{3} +3x^{2} -25x-75.

  • (x-1) - No
  • (x-3) - No
  • (x+3) - Yes
  • (x-5) - Yes
  • (x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

(x^{3} +3x^{2}) -(25x-75) =0.

⇒ Group 1: x^{3} +3x^{2} .

Group 2: - 25x +75 .

Pull out factor from each group,

⇒ Group 1: (x+3)(x^{2}).

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

Other factors are solved by the formula, a^{2}-b^{2} = (a+b) (a-b) .

(x+3)(x^{2} -25) = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0
3 years ago
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