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2 years ago

7

What is the formula for finding the volume of a cube? 2xx E^3 2x=3x(3+4)

2 answers:

ludmilkaskok [199]2 years ago

3 0

To find the volume for a cube you need to do length x width x height. make sure you put it as cm3 because it’s volume. hope it helps?

Rudiy272 years ago

3 0

$\sf \: The \: formula \: for \: finding \: the \: volume \: of \: a \: cube \: is \hookrightarrow \boxed{ \underline{ \bf{E}^{3} }} \\ \\ \sf \: The \: volume \: of \: the \: cube \: can \: be \: found \: by \: \\ \sf \: multiplying \: the \: edge \: length \: three \: times. \: For \: instance, \: \\ \sf \: if \: the \: length \: of \: an \: edge \: of \: a \: cube \: is \: \bf \: 4, \: \sf t he \: volume \\ \sf \: will \: be \longrightarrow \bf{4}^{3}.$

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Please help me out please

Ksivusya [100]

By comparing the perimeters, we can deduce the scaling factor:

$k = \dfrac{34}{20} = 1.7$

The areas scale with the square of the scaling factor, so the new area is

$19.6 \cdot 1.7^2 = 56.644$

7 0

3 years ago

Enter the range of data 37,45,20,34,28,80

Montano1993 [528]

Answer:

60

Step-by-step explanation:

To find the range, you subtract the largest number and the smallest number.

Largest number: 80

Smallest number: 20

80-20=60

8 0

3 years ago

Read 2 more answers

What is the equation of the graphed line written in standard form?

IrinaVladis [17]

Y=2x+4
y=2x-4
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5 0

3 years ago

Read 2 more answers

Questions in picture

zmey [24]

Answer:

z-test

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Step-by-step explanation:

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3 years ago

The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?

Jet001 [13]

Answer:

The roots are $x = (\frac{3}{2}, -2)$ , which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

In this question, we have that:

$2x^2 + x - 6 = 0$

Which is a quadratic equation with $a = 2, b = 1, c = -6$ . So

$\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49$

$x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}$

$x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2$

So the roots are $x = (\frac{3}{2}, -2)$ , which is given by option C.

3 0

3 years ago