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Sunny_sXe [5.5K]
3 years ago
5

Simplify the following expressions.

Mathematics
1 answer:
baherus [9]3 years ago
8 0
1. 36x + 4
2. 30n + 42
3. -24p + 32
4. 24p -28
5. 15m - 30
6. 5x + 45
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Step-by-step explanation:

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Read 2 more answers
1. Type an equation in the equation editor that uses 2 fractions with parentheses around one of them. Example: <img src="https:/
avanturin [10]

Answer:

i) \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}    \Rightarrow \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)4^{3} + 8^{2} + \sqrt{9}   \Rightarrow  4^{3} + 8^{2} + \sqrt{9}

iii) (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

Step-by-step explanation:

i) \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}    \Rightarrow \frac{3}{5} + (- \frac{1}{2}) = \frac{6}{10} - \frac{5}{10} = \frac{1}{10}

ii)4^{3} + 8^{2} + \sqrt{9}   \Rightarrow  4^{3} + 8^{2} + \sqrt{9}

iii) (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}} \Rightarrow \hspace{0.2cm}    (\frac{4}{5})^{2}. \sqrt[3]{8} \leqx^{3} - 3x + 6 \leq \sqrt{\frac{1}{3}}

7 0
4 years ago
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