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ale4655 [162]
3 years ago
10

412.638 in expanded form

Mathematics
2 answers:
choli [55]3 years ago
6 0
400+10+2+0.6+0.03+0.008
ser-zykov [4K]3 years ago
5 0
(4x100)+(1x10)+(2x1)+(6x1/10)+(3x1/100)+(8x1/1000)
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when constructing the incenter of a triangle, The inersection of all three of which type of line needs to be found
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denis-greek [22]

<u>Answer:</u>

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<u>Step-by-step explanation:</u>

x^2 + 12

First set the equation to 0

x^2 + 12

x^2 + 12 = 0

Second, get the 12 on the right side of the equal sign by adding a -12 to each side

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x^2 = -12

Square root both sides of the equal sign.

x^2 = -12

\sqrt{x^2} = \sqrt{-12}

Take the square root on left sides of the equal sign.

\sqrt{x^2} = \sqrt{-12}

x = \sqrt{-12}

Take the square root on the right side of the equal sign. Remember \sqrt{-1} = i

x = \sqrt{-12}

x = \sqrt{4}*\sqrt{-1}\sqrt{3}}

x = 2i\sqrt{3}

<u>AND</u>

x = -2i\sqrt{3}

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Step-by-step explanation:

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