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Zinaida [17]
3 years ago
10

A car loses 20% of its value every

Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

<u>20% loss a year with initial value of £6000 can be shown as function:</u>

  • V(t) = 6000*0.8^t

V(t) - is the value after t years

a) t = 1 year

  • V(1) = 6000*0.8 = £4800

b) t = 3 years

  • V(3) = 6000*0.8^3 = £3072

c) t = 8 years

  • V(8) = 6000*0.8^8 = £1006.63
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Show that (3+4)2−(3−4)2−(4)(4)=32
tatuchka [14]

Answer:

Explanation below

Step-by-step explanation:

(3+4)= 7

7+2 = 9

-(3-4) (Invisible one)

-3+4 add to the 9

10

10+2= 12

12-4=8

8×4 =32

Sorry if this seems a bit confusing, but its quite hard to show the process without paper.

Hope this helps! :)

8 0
3 years ago
Which inequality represents this sentence?
ycow [4]
B is the answer I’m 100% sure of it
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How to do this question
Bas_tet [7]

Answer:

x

Step-by-step explanation:

factor out both equations and then cancel any of the common factors. You should be left with 4x/4, which simplified is x

7 0
2 years ago
Solve for y<br> x+y= -15
Illusion [34]

X + y = -15. Subtract x from both sides.

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3 years ago
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A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses
Greeley [361]

Answer:

The original duration of the tour  is 18 days.

Step-by-step explanation:

Let

the number of days spent be T

Daily expenses be D

Initially ,

total tour expenses was 360

D \times T=360

D = \frac{360}{T}-------------(1)

If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3

(D + 4) \cdot(T -3) = 360---------------(2)

Expanding the eqaution(2)

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Substituting the value of D

(\frac{360}{T})T -3( \frac{360}{T}) + 4T -12 = 360

(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 360 + 12

(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 372

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( \frac{1080}{T}) + 4T= 372 - 360

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T = 18  and T = -15

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Substituting in equation (1) we get

D = \frac{360}{18}

D =  20

4 0
3 years ago
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