3 years ago

Inverse functions, PLEASE HELP I’m stuck

Mathematics

1 answer:

devlian [24]3 years ago

6 0

I learned how this week so I can help
3/4

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Paha777 [63]

Answer:

Is it A

Step-by-step explanation:

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3 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$

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3 years ago

Find the polynomial of least degree in standard form with the given roots:<br> x = 2, 3i

Dmitriy789 [7]

Answer:

x^3 - 2x^2 + 9x - 18.

Step-by-step explanation:

The complex roots occur in conjugate pairs so there are 3 roots 2, 3i and -3i.

So we have:

P(x) = (x - 2)(x - 3i)(x + 3i)

= (x - 2)(x^2 - 9i^2)

= (x - 2)(x^2 - 9*-1)

= (x - 2)(x^2 + 9)

= x^3 + 9x - 2x^2 - 18

= x^3 - 2x^2 + 9x - 18.

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asambeis [7]

Answer:319530474900

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maxonik [38]

Answer:

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Step-by-step explanation:

If you need an explanation just ask

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