9514 1404 393
Answer:
95 seconds
Step-by-step explanation:
At 5 seconds per box, pulling 3 boxes takes 3×5 = 15 seconds.
At 1 second per envelope, pulling 10+10+60 = 80 envelopes takes 1×80 = 80 seconds.
The total time required to provide the required envelopes is 15 +80 = 95 seconds.
Y= 11-2
B= 5-1
P=3divided by 7
Length of the mid-segment = (long base + short base) / 219 = (27 + short base) / 219 - (27 / 2) = short base / 2Multiplying both sides by 238 -27 = short baseshort base = 11
Source:http://www.1728.org/quadtrap.htm
Those expressions are already in scientific notation.
Jcodieigbbcusiifuc Heidi’s using forcurbside neci I think I