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bagirrra123 [75]
2 years ago
5

Each side of a hexagon is 10 inches longer than the previous side. what is the length of the shortest side of this hexagon if it

s perimeter is 401 inches?
Mathematics
1 answer:
MrRa [10]2 years ago
3 0

The length of the shortest side of the hexagon is; 41.833 inches

<h3>How to find the perimeter of a Polygon?</h3>

Let the length of the shortest side of the hexagon be x. Now, a hexagon has six sides and if the next side is 10 inches longer than the previous side, then the length of the six sides are;

x, x + 10, x + 20, x + 30, x + 40, x + 50

Perimeter is given as 401 inches. Thus;

x + x + 10 + x + 20 + x + 30 + x + 40 + x + 50 = 401

6x + 150 = 401

6x = 401 - 150

6x = 251

x = 251/6

x = 41.833 inches

Read more about Polygon Perimeter at; brainly.com/question/14490532

#SPJ1

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In the figure, △ABC is similar to △DEF. what is m∠1
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C. 139°

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What is the number of positive integers not larger than 210 and not divisible by 2, 3 or 7?
vladimir1956 [14]
Number of +ve integers divisible by 2 less than or equal to 210=a=210/2=105

number of +ve integers divisible by 3 less than or equal to 210=b=210/3=70

number of +ve integers divisible by 7 less than or equal to 210=c=210/7=30

number of +ve integers divisible by 2&3 less than or equal to 210=d=210/6=35

number of +ve integer divisible by 2&7 less than or equal to 210=e=210/14=15

number of +ve integer divisible by 3&7 less than or equal to 210=e=210/21=10

number of +ve integer divisible by 2&7&3 less than or equal to 210=e=210/42=5

<span>number of positive integers not larger than 210 and divisible by 2, 3 or 7=105+70+30-(35+15+10)+5

=150

so numbers not divisible=total-150
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