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bagirrra123 [75]
2 years ago
5

Each side of a hexagon is 10 inches longer than the previous side. what is the length of the shortest side of this hexagon if it

s perimeter is 401 inches?
Mathematics
1 answer:
MrRa [10]2 years ago
3 0

The length of the shortest side of the hexagon is; 41.833 inches

<h3>How to find the perimeter of a Polygon?</h3>

Let the length of the shortest side of the hexagon be x. Now, a hexagon has six sides and if the next side is 10 inches longer than the previous side, then the length of the six sides are;

x, x + 10, x + 20, x + 30, x + 40, x + 50

Perimeter is given as 401 inches. Thus;

x + x + 10 + x + 20 + x + 30 + x + 40 + x + 50 = 401

6x + 150 = 401

6x = 401 - 150

6x = 251

x = 251/6

x = 41.833 inches

Read more about Polygon Perimeter at; brainly.com/question/14490532

#SPJ1

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Answer:

c) .22

Step-by-step explanation:

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So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

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In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

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In the figure points A B C D and E are collinear. If AE = 38 and BD = 15
fredd [130]

Answer:

D. 30.5

Step-by-step explanation:

Given that A, B, C, D, and E are collinear,

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BD = 15, since segment BC = CD = DE, therefore

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Solve for BE

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45/2 = BE

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