Answer:
The correct option is;

Step-by-step explanation:
Here we have the formula for the confidence interval of the difference of two means where the population standard deviation is unknown based on the sample mean and sample standard deviation is given as follows;

Where:
= Mean of the first sample = 22 grams
= Mean of the second sample = 18 grams
s₁ = Sample standard deviation of the first sample = 3.2 grams
s₂ = Sample standard deviation of the second sample = 2.1 grams
n₁ = Sample size of the first sample = 100
n₂ = Sample size of the second sample = 100
= t value obtained from tables at 99% confidence level and 100 degrees of freedom = 2.626 = 2.63
Therefore, plugging in the values, we have;

Therefore, the correct option is
.
In this problem, you are looking at a pair of similar trapezoids. So we must be looking for a ratio between a side in the smaller trapezoid and the corresponding side in the bigger trapezoid. We are given the lengths of AB and EF, which we can use to find this ratio.
But before we do anything we must convert units so that all units are the same. Let's convert the 60 feet into inches. 60 feet is 720 inches.
Next, set up the ratio I mentioned earlier. If we set up the ratio so that it is smaller:larger, we would get 4:720, which simplifies to 1:180. Basically what this ratio says is that every 1 inch in the smaller trapezoid corresponds to 180 inches in the bigger trapezoid. Now we can use this ratio to find the lengths of the sides in the bigger trapezoid. Just multiply all the lengths of the smaller trapezoid by 180 to get the lengths for the bigger trapezoid. Finally, when we have all our side lengths, divide them all by 12 (because 12 inches in 1 foot) to get the measurements in feet.
From here, I'll let you find the total length yourself.
Complementary angles ⇒ the angles add up to 90°
∠A and ∠B are complementary ⇒ ∠A + ∠B = 90°
∠A + ∠B = 90°
Plug in the values for ∠A and ∠B:
(3x - 8) + (5x + 10) = 90
Open the brackets:
3x - 8 + 5x + 10 = 90
Combine like terms:
8x + 2 = 90
Subtract 2 from both sides:
8x = 88
Divide both sides by 8:
x = 11
Answer: x = 11
I don't know for sure, but I think there might be an error in the way you copied your function. In all of my dealings with these types of problems, I have learned the formula to be h(t) = 15 + 10t - 16t^2. Notice the plus in front of the "10t". This is due to the fact that if he pushes off of the overhang he would have an upward force of 10 feet per second as soon as his feet left the ground. The only thing pulling him back to Earth is gravity, modeled by the "-16t^2". This is derived from a bit of slightly advanced physics involving the gravitational constant, but let's work under my formula for a second...
Either way, we will wind up using the Quadratic Formula (or possibly factoring if the numbers are easy enough to work with). So let's start.
h(t)= 15 +10t - 16t^2
In order to use the QF or factoring I will need to make h(t)=0. Simply done by:
0= 15 +10t -16t^2
Looking at the numbers, I'd prefer to use the QF so here it is:

I know that my answer will need to be positive since you can't have a negative value when dealing with time, so I will eliminate the positive sign from the "+or-" part leaving me with:

And I know that a= -16, b= 10, and c=15. So all that's left to do is substitute and solve.
There's a decent amount of math that would be difficult and sloppy for me to do over the computer, but all you need to do is solve the rest of the equation and you would get your answer.
Exact answer:

or rounded answer: ≈1.31 seconds.
Hope this helps!
NoThisIsPatrick
Y doesn't change so it stays 3.
x will be 0, because the average of 0 and -2 is -1