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Mariana [72]
3 years ago
6

Plz help asap thanks xoxoxoxoxox

Mathematics
2 answers:
Leona [35]3 years ago
7 0
I cannot see a pictureesss
padilas [110]3 years ago
6 0
There is no picture
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Volume of a rectangular prism: V= Iwh ; Solve for I
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V=lwh

divide both sides by wh
\frac{V}{wh}=l
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3 years ago
ato must write 60 percent of a 20-page report by tomorrow. Kato wants to determine the number of pages that he needs to write by
ivanzaharov [21]

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Step 4

Step-by-step explanation:

because 100/20=5

so 60/5=12

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3 years ago
"Polio has a basic reproduction number (R0) = 5. The vaccine is very good; in fact, polio vaccine is 99% effective when two foll
yulyashka [42]

Answer:

0.81

Step-by-step explanation:

Herd immunity or community immunity is the immunity seen after vaccination of a population wherein the large portion of the population becomes immune to the pathogen. It depends on vaccine efficacy and vaccination rate.

The reproduction number R_o is a factor indicating the number of people that can be infected by the person with the disease. If Ro=5 then one infected person can infect 5 people with Polio virus.

V_c= q_c/E

V_c= Vaccine coverage

q_c= herd immunity threshold

E= Vaccine efficacy= 99%=0.99

q_c=1-1/R_o= 1-1/5=0.8

V_c= q_c/E

V_c= 0.8/0.99= 0.808= 0.81

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5 0
3 years ago
3(x+4)=16 solve for x
MAXImum [283]
Hope you get it
X=4/3

6 0
3 years ago
Read 2 more answers
→WILL GIVE BRAINLIEST←
raketka [301]

Answer:

a. 2,727

b. (85.6%, 87.6%)

Step-by-step explanation:

The percentage of the adults aged 57 through 85 that used at least one prescription medication = 86.6%

a. The expected number of the 3,149 subjects aged 57 through 85 that used at least one prescription medication = 3,149 × 86.6/100 = 2,727.034 ≈ 2,727 (subjects)

b. The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is given as follows;

CI=\hat{p}\pm z\times \sqrt{\dfrac{\hat{p} \cdot (1-\hat{p})}{n}}

Where;

\hat p = 86.6/100= 0.866

n = 3,149

z = The z-value at 90% confidence level = 1.645

Therefore, we get the following confidence interval of the percentage of adults (rounded to one decimal place as required);

\left (0.866 - 1.645\times \sqrt{\dfrac{0.866 \times (1-0.866)}{3,149}}\right) \times  100 \%  \approx 85.6 \%

\left( 0.866 + 1.645\times \sqrt{\dfrac{0.866 \times (1-0.866)}{3,149}} \right) \times 100 \%  \approx 87.6 \%

The 90% confidence interval, of the percentage C.I. ≈ (85.6%, 87.6%).

5 0
3 years ago
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