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3 years ago

I need help with this please!!

Mathematics

2 answers:

Virty [35]3 years ago

8 0

Answer: Sum ids jdlfkajskldfjasiejrflk

Step-by-step explanation:

guajiro [1.7K]3 years ago

8 0

Answer:

The correct choices would be A, C, D & F. Correct me if I'm wrong :)

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Identify the probability to the nearest hundredth that a point chosen randomly inside the rectangle is in the triangle. HELP PLE

sashaice [31]

Answer:

$0.02$

Step-by-step explanation:

we know that

The probability that a point chosen randomly inside the rectangle is in the triangle is equal to divide the area of the triangle by the area of rectangle

Let

x-----> the area of triangle

y----> the area of rectangle

P -----> the probability

$P=x/y$

<em>Find the area of triangle (x)</em>

$A=(1/2)(5)(2)=5\ in^{2}$

<em>Find the area of rectangle (y)</em>

$A=18*12=216\ in^{2}$

<em>Find the probability P</em>

$P=5/216=0.02$

5 0

3 years ago

2. Angelica reflects ABCDE over the yaxis and translates to Does her transformed figure match A'B' C D'Ef not describe honored f

Monica [59]

Answer:

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do u like it

Step-by-step explanation:

5 0

3 years ago

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Katie wants to collect over a hundred seashells she already has 34 seashells in her collection each day she finds 12 more seashe

strojnjashka [21]

Answer:

Step-by-step explanation:

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2 years ago

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Circumference (rounding)

LUCKY_DIMON [66]

Answer:

19.5

Step-by-step explanation:

Circumference is radius multiplied by 2, then multiplied by pi.

3.1 × 2= 6.2

6.2 × π= 19.477 ≈ 19.5

π also equals 3.14

4 0

3 years ago

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If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

Compare the result with given expression to get:

a = 4/3 and b = 0

4 0

2 years ago