We will have a system of equations, and we are going to solve it by using substitution.
Let's make the equations.
x+y+z=2100
z+y=x
Since y and z are equal, I think it is easier for us to have them as one variable for now. Let the value of z and y be a.
These are the equations now.
x+2a=2100
2a=x
Since the second equation is giving the value of x, let it replace the value of x also in the first equation.
2a+2a=2100
4a=2100
2100÷4= 525
so, x and y equal 525. Let's put this in our original equation.
x+525+525=2100
x+ 1,050= 2,100
x= 1,050
So, x=1,050, y= 525 =z.
2p=p(1+0.0075/12)^12t
12t=log(2)/log(1+0.0075/12)
Can you solve for t
I think that is the answer because it says 2/5 where two rows are shaded and three more rows remain unshaded so, when you add that three and two it's altogether 5, so I think that is the answer, please check out the document I have uploaded.
Millimeters, centimeters, inches, yards, meters
L = 10 mw = 11 mh = 5 md = 15.6844 mS = 430 m²V = 550 m³ x 2 = 1100m³
Agenda:l = lengthw = widthh = heightd = diagonalS = surface area V = volume
