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Art [367]
3 years ago
5

There are 16 tablespoons in one cup. Which table correctly relates the number of cups to the number of tablespoons?

Mathematics
2 answers:
lana [24]3 years ago
5 0

Answer:  The first table

Step-by-step explanation:

1:16

2:32

4:64

8:128

masya89 [10]3 years ago
3 0

Answer:

The first one that goes 1-8 under the cups.

Step-by-step explanation:

Since theres 16 tablespoons in 1 cup, it goes up by 16 per cup. So, for 2 cups, it's 2 x 16, for 3 cups, its 3 x 16, and so on. If you were to do that the first table is the only one that matches.

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CaHeK987 [17]

Answer:

n = -8

Step-by-step explanation:

Given the expression

(-2y-3) + (-6y-5) =  (ny -8),

Expanding the LHS

-2y-3 - 6y -5 = ny - 8

-2y-6y-3-5 = ny - 8

-8y - 8 = ny - 8

Compare both sides

-8y = ny

-8 = n

Swap

n = -8

Hence the value of n is -8

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Cuantos planetas hay
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8

Step-by-step explanation:

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4 years ago
Create your own question about finding the area or circumference of a shape on the basketball court. As you choose your shape, m
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Step-by-step explanation:

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4 years ago
A cylindrical base has a diameter of 6 inches. At the bottom of the vase, there are 9 marbles, each of the diameter 3 inches. Th
alexandr1967 [171]

Answer:

\sf C. \quad \pi (3\:in)^2(12\:in)-9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)

Step-by-step explanation:

To find the volume of water in the vase, subtract the volume of the marbles from the volume of the cylindrical vase.

..............................................................................................................................

The marbles can be modeled as <u>spheres</u>.

<u>Volume of a sphere</u>

\sf V=\dfrac{4}{3}\pi r^3 \quad \textsf{(where r is the radius)}

<u>Radius</u>

\sf r = \dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

Therefore, the volume of 9 marbles, each of diameter 3 inches is:

\sf Volume & = \sf 9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)

..............................................................................................................................

The vase can be modeled as a <u>cylinder</u>.

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad \textsf{(where r is the radius and h is the height)}

Therefore, the volume of a cylinder with a base of diameter 6 in and a height of 12 in is:

\sf Volume =\pi (3\:in)^2(12\:in)

..............................................................................................................................

<u>Volume of water</u>

<u />

\begin{aligned}\implies \sf Volume\:of\:water & = \sf Volume\:of\:vase- Volume\:of\:marbles\\& = \sf \pi (3\:in)^2(12\:in)-9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)\end{aligned}

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2 years ago
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