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Elena L [17]
3 years ago
11

Solve the following equation by completing the square. 1/4x^2+x+1/4=0

Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

D. X=-2+sqrt(3) or -2-sqrt(3)

x_{1} =-2+\sqrt{3} \\x_{2} =-2-\sqrt{3}

Step-by-step explanation:

Quadratic Equation given:

$\frac{1}{4} x^2+x+\frac{1}{4}=0$

In order to get rid of the fractions, multiply both sides by 4.

$\frac{1}{4}x^2\cdot \:4+x\cdot \:4+\frac{1}{4}\cdot \:4=0\cdot \:4$

We get:

x^2+4x+1=0

x^2+4x+4-4+1=0

Completing the square:

(x+2)^2-4+1=0\\

(x+2)^2-3=0

(x+2)^2=3

x+2=\pm\sqrt{3}

x=-2\pm\sqrt{3}

x_{1} =-2+\sqrt{3} \\x_{2} =-2-\sqrt{3}

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