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adell [148]
3 years ago
8

WILL MARK BRAINLYEST

Mathematics
2 answers:
pashok25 [27]3 years ago
5 0

Answer:

y+1=\frac{6}{11}(x+4)

The image below shows proof that the point-slope equation y+1=\frac{6}{11}(x+4) is the correct equation in point-slope form that the line passes through the points (7, 5) and (-4, -1)

<em>Hope this helps!</em> :)

Veseljchak [2.6K]3 years ago
3 0

Answer:

y - 5 = 6(x - 7)

Step-by-step explanation:

yes

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Free points bc I don't know how to use these things.
34kurt

Answer:

thank you hahahahahahaha <3

3 0
3 years ago
Read 2 more answers
Solve for n: -1/2 (n + 8) +3/4
vlabodo [156]

\frac{1}{2} (n+8) + \frac{3}{4}

\frac{1(n+8)}{2}  +  \frac{3}{4}

\frac{n+8}{2}  +  \frac{3}{4}

\frac{2(n+8)}{4}  + \frac{3}{4}

\frac{2(n+8) + 3}{4}

\frac{2n + 16 +3}{4}

\frac{2n + 19}{4}

7 0
2 years ago
Because gambling is a big​ business, calculating the odds of a gambler winning or losing in every game is crucial to the financi
IRISSAK [1]

Answer:

a) 0.1165

b) 0.0983

c) 0.000455

d) 0.787

e) 0.767

Step-by-step explanation:

5 ​bars, 4 ​lemons, 3 ​cherries, and a bell

Total = 5+4+3+1 = 13

The probability of getting a bar on a slot, P(Ba) = 5/13 = 0.385

A lemon, P(L) = 4/13 = 0.308

A cherry, P(C) = 3/13 = 0.231

A bell, P(Be) = 1/13 = 0.0769

a) Probability of getting 3 lemons = (4/13) × (4/13) × (4/13) = 256/2197 = 0.1165

b) Probability of getting no fruit symbol

On each slot, there are 4+3 = 7 fruit symbols.

Probability of getting a fruit symbol On a slot = 7/13

Probability of not getting a fruit symbol = 1 - (7/13) = 6/13 = 0.462

Probability of not getting a fruit symbol On the three slots = 0.462 × 0.462 × 0.462 = 0.0983

c) Probability of getting 3 bells, the jackpot = (1/13) × (1/13) × (1/13) = 1/2197 = 0.000455

d) Probability of not getting a bell on the 3 slots

Probability of not getting a bell on one slot = 1 - (1/13) = 12/13 = 0.923

Probability of not getting a bell on the 3 slots = (12/13) × (12/13) × (12/13) = 1728/2197 = 0.787

e) Probability of at least one bar is a sum of probabilities

Note that Probability of getting a bar = 5/13 and probability of not getting a bar = 8/13

1) Probability of getting 1 bar and other stuff on the 2 other slots (this can happen in 3 different orders) = 3 × (5/13)×(8/13)×(8/13) = 960/2197 = 0.437

2) Probability of getting 2 bars and other stuff on the remaining slot (this can also occur in 3 different orders) = 3 × (5/13)×(5/13)×(8/13) = 600/2197 = 0.273

3) Probability of getting 3 bars on the slots machine = (5/13) × (5/13) × (5/13) = 125/2197 = 0.0569

Probability of at least one bar = 0.437 + 0.273 + 0.0569 = 0.7669 = 0.767

5 0
3 years ago
How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
lidiya [134]

Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?

Solution:

Here we are given with the sides of the triangle as 5m, 16m and 5.

As the Triangle inequality we know that

The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.

Hence no triangle can be made.

So the correct option is None.

Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?

Solution:

Here we are given with the sides of the triangle as 6m, 2m and 7m.

As the Triangle inequality we know that

The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.

Hence one triangle can be formed.

So the correct option is  one.

8 0
3 years ago
Need help with this problem
insens350 [35]
That equation just equals ln(e^(-4/3)) which can be simplified to -4/3 because ln and e cancel each other out only leaving the power
4 0
3 years ago
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