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Amanda [17]
3 years ago
5

in 2000, Jonesville had a population of 15,000. in 2001, the population was 16250 and in 2002, the population was 17,500. if the

population grew at the same constant rate each year, which model describes the population growth for n years after 2000?
Mathematics
2 answers:
lesya [120]3 years ago
8 0
Population (p) = 1,250n + 15,000
tester [92]3 years ago
4 0

In year 2000, the population was 15,000.

In year 2001, the population was 16,250.

In year 2002, the population was 17,500.

The population growth from year 2000 to year 2001 was (16,250-15,000) = 1,250.

The population growth from year 2001 to year 2002 was (17,500-16,250) = 1,250.

So the slope of the line would be m = 1250.

And y-intercept would be the initial population i.e. b = 15,000.

So the equation of line is y = 1250x + 15000.

Hence, n years after 2000, the population would be P = 1250n + 15000.

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Because this is an isosceles triangle, we know that the bottom two angles are equal.  We also know that the sum of the angles inside a triangle will always come to 180°.  With that in mind, we can simply subtract 38° from 180° and divide by two to get the correct answer.

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