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n200080 [17]
3 years ago
9

Solve the polynomial equation by factoring. x^3+2x^2-9x-18=0

Mathematics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

This can be factored to (x + 3)(x - 3)(x + 2) = 0

So x is equal to 3, -3 and -2

Step-by-step explanation:

x³ + 2x² - 9x -18 = 0

Let's try dividing by (x + 3) as that looks like it might be a factor.  We'll use long division:

                    x²  - x - 6

        x + 3  }  x³ + 2x² - 9x -18

                    x³ + 3x²

                           -x² - 9x

                           -x² - 3x

                                -6x - 18

                                -6x - 18

                                         0

Perfect!  So (x + 3) is a factor, giving us:

(x + 3)(x² - x - 6)

the remaining quadratic can be factored more easily:

(x + 3)(x² - x - 6)

= (x + 3)(x² + 2x - 3x - 6)

= (x + 3)(x[x + 2] - 3[x + 2])

= (x + 3)(x - 3)(x + 2)

Now we can solve it easily as we know that's equal to zero, so x can be equal to 3, -3, and -2

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Please answer this question now
Alexeev081 [22]

Answer:

Area = 400.4 m^2

Step-by-step Explanation:

Given:

∆UVW,

m < U = 33°

m < V = 113°

VW = u = 29 m

Required:

Area of ∆UVW

Solution:

Find side length UV using Law of Sines

\frac{u}{sin(U)} = \frac{w}{sin(W)}

U = 33°

u = VW = 29 m

W = 180 - (33+113) = 34°

w = UV = ?

\frac{29}{sin(33)} = \frac{w}{sin(34)}

Cross multiply

29*sin(34) = w*sin(33)

Divide both sides by sin(33) to make w the subject of formula

\frac{29*sin(34)}{sin(33)} = \frac{w*sin(33)}{sin(33)}

\frac{29*sin(34)}{sin(33)} = w

29.77 = w

UV = w = 30 m (rounded to nearest whole number)

Find the area of ∆UVW using the formula,

area = \frac{1}{2}*u*w*sin(V)

= \frac{1}{2}*29*30*sin(113)

= \frac{29*30*sin(113)}{2}

Area = 400.4 m^2 (to nearest tenth).

4 0
3 years ago
Mona wants to buy carpet for a floor in her house.
Gnesinka [82]
What are the prices?
7 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

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3 years ago
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Phoenix [80]

Answer:

The slope is approximately 2 and the y-intercept is approximately 3.

Step-by-step explanation:

I don't know if this is right but I hope it is have an amazing day.

5 0
2 years ago
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A line passes through (−1, 7) and (2, 10).
Murljashka [212]
The formula is y=mx+b
To get the slope or m, use this formula
(the second y minus the first y)/(the second x minus the first x)
Now set it up.
(10-7)/(2--1)
3/3=slope is 1.
y=1x+b

Insert one of the points for x and y.
i will do (-1,7)
7=1(-1)+b
7=-1+b
8=b
Insert this into the final equation:
y=1x+8

Try it out. If you're not sure, try both points. If it works, then you set it up correctly.
6 0
3 years ago
Read 2 more answers
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