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o-na [289]
2 years ago
13

A) what is the simplified product of seven-fourths divided by eight-fifths as an improper fraction

Mathematics
2 answers:
Alex73 [517]2 years ago
4 0

Answer:

<h3>A) </h3>

First were going to put our numbers in perspective.

\frac{7}{4} ÷ \frac{8}{5}

But to find the improper fraction, we have to <em>cross multiply</em> these numbers.

\frac{7}{4} × \frac{8}{5}

<em>7 x 5 = 35.  </em>

<em>4 x 8 = 32.</em>

Now we have our<em> improper fraction </em>is  \frac{35}{32}

<h3>B)  </h3>

To turn our improper fraction into a <em>mixed number</em>, we will use <em>division</em>.

We know that the 32 can only go into 35 <u><em>one</em></u> time.  We also know that the bottom number <em><u>always</u></em> stays the same.  So our equation will look somewhat like this.

1\frac{?}{32}

Now to fine the top number we will have to<em> subtract 35 from 32</em> because we already know that 32 can go into 35 <u><em>one</em></u> time, so <em>35 - 32 = 3</em>.  So are mixed number will look like this.

1\frac{3}{32}

This is our <em>answer!</em>

Maslowich2 years ago
4 0

Answer:

7/4 ÷ 8/5

A. First, we need to do the reciprocal of 8/5.

7/4 x 5/8 = 35/32

B. Now, we need to convert it into a mixed number. Divide 35 by 32. 32 goes into 35 one time. 35 - 32 = 3, so remainder 3. We use 1 as the whole number since 32 goes into 35 one time. We use the remainder 3 as the numerator, and 32 as the denominator.

1 3/32

Hope this helps u have a great day :)

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Write a quadratic function for each graph described.
user100 [1]

Answer:

y=2x^2-\frac{4}{3}x-\frac{10}{3}

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

so

we can write the equation of the parabola as

y=a(x+1)(x-\frac{5}{3})

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

40=a(5+1)(5-\frac{5}{3})

40=a(6)(\frac{10}{3})

40=20a\\a=2

substitute

y=2(x+1)(x-\frac{5}{3})

apply distributive property

y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}

see the attached figure to better understand the problem

6 0
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Answer:

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The critical values for a two tailed test are the values of t that are placed in the limit of the significance level. If the test statistic t is greater than this critical values, the null hypothesis is rejected.

To determine this values, we first divide the significance level by 2. With a t-table or app, we can determine the t values for P(x>|t|)=α/2=0.05.

In this case, for a degrees of freedom DF=20-2=18, we have the test statistic t=±1.7341 that satisfies the condition.

Solution of the hypothesis test

In this problem we want to prove if the slope of the regression model is different from 0, by means of a hypothesis test.

First, we state the null and alternative hypothesis:

H_0: B_1=0\\\\H_1: B_1 \neq 0

The significance level is \alpha=0.10.

The degrees of freedom for a simple regression model is:

DF=n-2=20-2=18

The standard error estimated of the slope is 0.0053.

The test statistic t is calculated as:

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The P-value for a two-tailed test for a t=4.0377 and DF=18 is:

P=0.00078

The P-value is smaller than the significance level, so the effect is statistically significant. The null hypothesis is rejected.

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Read 2 more answers
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