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3 years ago

Six times a number is greater than 20 more than that number. Which are the possible values of that number?

2 answers:

4 0

I don't know how to make a 'greater than' sign.

6x is greater than x + 20
6x - x is greater than 20
5x is greater than 20
x is greater than 20 divided by 5
x is greater than 4

So, any number greater than 4 will work in this equation.

liberstina [14]3 years ago

4 0

6 times a number is greater than 20 more than that number

6 times a number means 6 times x
is greater than means >
20 more than that number means 20+x

6x>20+x
minus x both sides
5x>20
divide both sides by 5
x>4

x is any number more than 4

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Evaluate the expression 7x + y when x = 2 and y 6

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7(2) + 6
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20
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In order to be invited to tutoring or extension activities a students performance 20 point higher or lower than average for the

GalinKa [24]

Answer:

Step-by-step explanation:For the student to be considered for the tutoring or extension activities, his/her score must be 20 points lower or higher than the average.

The average is given as 105, that means:

Minimum score to be considered = 105 - 20 = 85

Maximum score to be considered = 105 + 20 = 125

If p represents the performance of a student, then this inequality will be represented as follows:

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3 years ago

FIFO does not assume which of the following? sell old inventory first.or sell the new inventory first

pentagon [3]

First In First Out.

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so it doesn't assume to sell the new one first.

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3 years ago

Express the null hypothesis and the alternative hypothesis in symbolic form. The owner of a football team claims that the averag

Brilliant_brown [7]

Answer:

$H_{0}: \mu \leq 63500\\H_A: \mu > 63500$

Step-by-step explanation:

We are given the following in the question:

The owner of a football team claims that the average attendance at games is over 63,500.

He wants to justify that the team needs to be moved to a larger stadium outside the city.

If the attendance is larger than 63,500 the team would be moved to a larger stadium and if it is less than or equal to 63,500 that it would not.

Thus, the null and alternate hypothesis will be designed as:

$H_{0}: \mu \leq 63500\\H_A: \mu > 63500$

The null hypothesis says that the average attenders is equal to or less than 63,500 and alternate supports the claim that the attenders average is greater than 63,500.

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3 years ago