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Alex
3 years ago
11

Jody has 4 red marbles, 6 blue marbles, and 9 yellow marbles. What is the ratio of red marbles to blue marbles?

Mathematics
2 answers:
Natalija [7]3 years ago
8 0

Answer:

2:3

Step-by-step explanation:

First, create the ratio by putting the numbers together:

There are 4 red and 6 blue marbles:

4:6

Since both of these are divisible by 2, it can be simplified:

4:6

2:3

So, the ratio of red marbles to blue marbles is 2:3

Eduardwww [97]3 years ago
7 0

Answer: 4 to 6 marbles

Step-by-step explanation:

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*****************************************

Answer: \frac{150}{31}

<u>Step by step explanation:</u>

log₆(5x + 6) - log₆(x - 4) = 2

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**********************************************************

Answers:

  • a. (-1, -5)
  • b. up
  • c. x = -1
  • d. \frac{-2+\sqrt{15}}{3} and\frac{-2-\sqrt{15}}{3}
  • e. -2
  • f. see attachment
  • g. domain (-∞, ∞)  range [-5, ∞)

<u>Explanation:</u>

f(x) = 3x² + 6x - 2

      a=3  b=6 c=-2

x = \frac{-b}{2a} =\frac{-6}{2(3)} = \frac{-6}{6} = -1

Axis Of Symmetry: x = -1

f(-1) = 3(-1)² + 6(-1) - 2

       = 3 - 6 - 2

       = -5

Vertex: (-1, -5)

x = \frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

  = \frac{-6+/-\sqrt{6^{2}-4(3)(-2)}}{2(3)}

  = \frac{-6+/-\sqrt{36+24}}{6}

  = \frac{-6+/-\sqrt{60}}{6}

  = \frac{-6+/-2\sqrt{15}}{6}

  = \frac{-2+/-\sqrt{15}}{3}

x-intercepts: \frac{-2+/-\sqrt{15}}{3}



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