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Zinaida [17]
3 years ago
6

WILL GIVE BRAINLIST kai has 32 he wants to put the same number of tickets into 4 boxs wich number sentence could be used to find

the number of tickets kai should put in each box
QUESTOINS:
A; 4+__=32
B; 4x__=32
C; 32-__=4
D; 32x__=4
Mathematics
2 answers:
kotykmax [81]3 years ago
4 0

Answer:

it is B

Step-by-step explanation:

now brainliest 5 stars and heart please

grandymaker [24]3 years ago
4 0

Answer:

IT would be B

Step-by-step explanation:

If you multiply 4 x 8 = 32 will complete the answer

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Answer: 30, -36, 42

Step-by-step explanation:

So basically the pattern is just the next number that is a multiple of six, but every other number is negative. 6 is 6 times 1, -12 is 6 times -2, 18 is 6 times 3, -24 is 6 times -4, 30 is 6 times 5, -36 is 6 times -6, and 42 is 6 times 7

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Compare the backpack weights for the students in the three classes.
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Seventh graders backpacks weigh less than Eleventh graders back packs
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The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
3 years ago
If f(x)=-x^2+6x-1 and g(x) =3x^2-4x-1, find (f-g)(x)
asambeis [7]

Answer:


Step-by-step explanation:

Given,

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we know,

(f-g)(x)=f(x)-g(x)

So, here we get

(f-g)(x)

=f(x)-g(x)

=-x^{2} +6x-1-(3x^{2} -4x-1)

=-x^{2} +6x-1-3x^{2} +4x+1

=-x^{2}-3x^{2} +6x+4x-1+1

=-4x^{2} +10x

So, the answer is

-4x^{2} +10x

8 0
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Answer:

575 meters

Step-by-step explanation:

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