Identify which functions have complex roots by selecting the function names on the provided coordinate plane,

RideAnS [48]

Since the number of members attending is 40, you can eliminate 17 as a possible answer, as it is smaller than 40. You can also eliminate 240 because 40 members is 60%, so the answer must be less than 80. You are now left with 67 and 73.

It is (a) because 40 divided by 67 = 0.597. 0.597 x 100 = 59.7% which is rounded to 60% of the club

4 0

3 years ago

Read 2 more answers

Enter the explicit rule for the geometric sequence. 9,6,4,83,…

soldier1979 [14.2K]

Answer:

a_n = 2^(n - 1) 3^(3 - n)

Step-by-step explanation:

9,6,4,8/3,…

a1 = 3^2

a2 = 3 * 2

a3 = 2^2

As we can see, the 3 ^x is decreasing and the 2^ y is increasing

We need to play with the exponent in terms of n

Lets look at the exponent for the base of 2

a1 = 3^2 2^0

a2 = 3^1 2^1

a3 = 3^ 0 2^2

an = 3^ 2^(n-1)

I picked n-1 because that is where it starts 0

n = 1 (1-1) =0

n=2 (2-1) =1

n=3 (3-1) =2

Now we need to figure out the exponent for the 3 base

I will pick (3-n)

n =1 (3-1) =2

n =2 (3-2) =1

n=3 (3-3) =0

8 0

3 years ago

Help please!!! I dont understand these questions currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

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4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago

Which is the longest? 100mm, 5cm,1/2m

GenaCL600 [577]

Answer:100mm

Step-by-step explanation:

7 0

3 years ago

To find 8 ×17, I double and halve

anastassius [24]

Answer:

what is the question?

Step-by-step explanation:

6 0

3 years ago