Answer:
a) Cumulative
Relative cumulative Relative
Class interval midpoint frequency frequency frequency frequency
0 -50 25 20 0.40 20 0.40
50 -100 75 16 0.32 36 0.72
100 -150 125 8 0.16 44 0.88
150 -200 175 2 0.4 46 0.92
200 -250 225 2 0.4 48 0.96
250 -300 275 0 0.0 48 0.96
300 -350 325 0 0.0 48 0.96
350 -400 375 2 0.4 50 1
50 1
The solution of part (b),(c),(d) and (e) is in attached word file
Step-by-step explanation:
In part a) we take the interval size of 50 and then the resulting 8 classes are 0-50,50-100,100-150,150-200,200-250,250-300,300-350,350-400. The mid points are calculating by adding lower class interval and upper class interval and then dividing it by 2 such as for 1st class 0+50/2=25. The column frequency represents the number of data values occurring in the respective class. Cumulative frequency is computed by adding the frequency of respective class to next class frequency.It remains same for 1st class and for the 2nd class 20+16=36 and so on. The relative frequency is computed by dividing the frequency by the sum of frequency such as for the 1st class 20/50=0.4 . The cumulative relative frequency is calculated by the same procedure by which the cumulative frequency is calculated.
b) The frequency histogram is constructed by taking the frequency on y-axis and data set values on x-axis. The resulting histogram is rightly skewed.
c) A frequency polygon is constructed by making the line chart and considering the frequency on y-axis and data set values on x-axis.
d) The relative frequency histogram is constructed by taking the relative frequency on y-axis and data set values on x-axis. The resulting histogram is rightly skewed.
e) An ogive is constructed by making the line chart and considering the cumulative frequency on y-axis and data set values on x-axis.
