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Alina [70]
3 years ago
7

Which of the following choices evaluates (-x)^2 when x=-1 Answers: 1)1 2)-2 3)-1

Mathematics
1 answer:
MissTica3 years ago
7 0
(-(-1))^2
(1)^2
1 x 1
=1

Answer: 1
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Which is greater -3 or -1/3 ?​
GenaCL600 [577]

Answer:

<u>-1/3</u>

Step-by-step explanation:

because it is a negative number and closer to zero than -3 is making it greater, becuase it is closer to a positive number.

6 0
2 years ago
Read 2 more answers
Help quick! I'll mark your answer as the brainliest if your answer is correct!
Anna007 [38]

Answer:

They would never intersect because they are parallel lines. You can tell they are parallel lines because they have the same slope and they have a different y-intercept. However, this doesn't mean that there was no solutions, there were, thats how i was able to tell what their slopes and y-intercepts were. So if there is an answer that you can choose from that explains that they won't intersect because they are parallel then that is the correct answer. It may be C, but I would see if there is another option.

8 0
3 years ago
The Mason family's bill for dinner is $55.73. How much should they tip their server? (Assuming they tip the normal 15%)
Lisa [10]

Answer:$8.36

Step-by-step explanation:

Change % to decimal and multiply

15% =.15

55.73 x .15 = 8.3595

5 0
4 years ago
What is the nth term for the sequence 5 , 14 , 29 , 50 , 77
Marina86 [1]
The answer would be 3n^2 + 2.

This can be found/proven by replacing "n" with term number (1,2,3,4...), then solving to get the final number. For example 3 * 1^2 + 2. You would first do 1^2, which is 1. Next, you would multiply 1 by 3, to get 3. Finally, you'd and the 2 to get 5. 5 is the 1st term, and you can use this same equation to get the rest of the terms you need.

I hope this helps!
8 0
3 years ago
Find the product. √5(2+√7) A)2√5+√35 B)√45 C)2√5+2√7 D)√10+√35
OverLord2011 [107]

Answer:

\huge \boxed{2\sqrt{5} +\sqrt{35}}

Step-by-step explanation:

\sqrt{5} (2+\sqrt{7} )

Expand brackets.

\sqrt{5} (2)+\sqrt{5}(\sqrt{7} )

2\sqrt{5} +\sqrt{5} \sqrt{7}

Apply radical rule : \sqrt{a} \sqrt{b} =\sqrt{ab}

2\sqrt{5} +\sqrt{5 \times 7}

2\sqrt{5} +\sqrt{35}

7 0
3 years ago
Read 2 more answers
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