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kolezko [41]
3 years ago
13

The world's population is expected to grow at a rate of 1.3% per year until at least the year 2020. In 1994 the total population

of the world was about 5,642,000,000 people. Use the formula Pn = P0ein to predict the world's population, Pn, n years after 1994, with P0 equal to the population in 1994 and i equal to the expected growth rate. What is the world's predicted population n the year 2020, rounded to the nearest million?
Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0
The solution to your problem is as follows:

Given: 
P₀ = 5,642×10^6 people, 
i = 1.3% = 0.013 per year, 
n = 2020 - 1994 = 26 years, 

We get: 
<span>
Pn = P₀ e^(i.n) </span>
. . .= 5,642×10^6×e^(0.013×26) 
<span>. . .= 7,911×10^6 people

Therefore, the </span>the world's predicted population in the year 2020 is <span>7,911×10^6 people.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
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Answer:

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

Step-by-step explanation:

1) Data given and notation

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X=282 represent the people that regularly watch the TV station’s news program

\hat p=\frac{282}{830}=0.340 estimated proportion of people that regularly watch the TV station’s news program

p_o=0.38 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:  

Null hypothesis:p\geq 0.38  

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When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

4) Statistical decision  

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The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

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