What happens to the value of the expression 150-j150−j150, minus, j as jjj decreases?
1 answer:
Answer:
The value of the expression increases as j decreases
Step-by-step explanation:
Let
As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.
For example:
When j = 1, f(j) = 150 - (300*1) = -150
When j = 0.5, f(j) = 150 - (300*0.5) = 0
When j = 0. f(j) = 150 - (300*0) = 150
It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases
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Answer:
307 paces
Step-by-step explanation:
First, lets convert Robert's pace to metres. (cm > m)
75cm = (75/100)m
= 0.75m
Number of Full Paces = Length of Bridge / 1 Full Pace
=
See , we must have full paces, and in this case we are finding the minimum number of paces, so we will be looking at the lowest possible whole number, which in this case, is 307 paces.