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AlekseyPX
3 years ago
9

The angular velocity of a point on a circle with radius of 12 feet is 15 radians per second. Find the speed of the point on the

circle.
Mathematics
2 answers:
Lyrx [107]3 years ago
5 0
Angular speed: 
(24*pi)*(15 pi/2pi) ft/sec:
565 ft/sec 
IRINA_888 [86]3 years ago
4 0

Answer:

v=180frac{ft}{sec}

Step-by-step explanation:

Givens:

  • r=12 \ ft
  • \omega = 15 \frac{rad}{sec}

The problem is asking for the speed of the point on the circle, that is, the linear speed, which definition is: v=r \omega

Replacing given values:

v=12 \ ft (15\frac{rad}{sec})=180\frac{ft}{sec}

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Galina-37 [17]

Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is (x_1,y_1)=(-3, 2)

Equation of a circle with center (h,k) and radius 'r' is given as:

(x-h)^2+(y-k)^2=r^2

Here, (h,k)=(5,-4)

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

r^2=(h-x_1)^2+(k-y_1)^2

Using distance formula for the points (5, -4) and (-3, 2), we get

r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

4 0
4 years ago
The oblique pyramid has a square base.
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Good evening ,

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Answer:

the volume of the pyramid = 5cm³

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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A train traveling at 10m/s slows down to a complete stop in 20s. What is the
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Answer:

The acceleration of the train is 0.5m/s²

Step-by-step explanation:

Given

Velocity of the train = 10m/s

Time taken = 20 s

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In other words, acceleration is calculated by dividing velocity by time.

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