1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
r-ruslan [8.4K]
3 years ago
15

Im so confused all i know is that it isn't C

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

B.

Step-by-step explanation:

The answer would be B. because 2/3 as a decimal is 0.66666666...... and so on. 2/3 as a percent is 66.66666...... and so on.

2/3 is just 2 divided by 3, that gets you 0.66666.....  2/3 = 0.6666..... (decimal)

Now you know the decimal. The rule to get a percent is to move the decimal point two places to the right to get the percent.

hodyreva [135]3 years ago
3 0
Well I’m not 100 percent sure but I believe it’s b
You might be interested in
Which list shows all the factors of 36?
Nataly [62]

Answer:

the first one.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Out of 28 teenagers and adults, people, 12 adults attended a music concert. what is the ratio of teenagers to attendees?
Naddika [18.5K]

Answer:

I believe it would be 14 to 28

5 0
2 years ago
Multiply.
MissTica
The answer is B 3x^4-13x^3-x^2-11x+6
7 0
3 years ago
Use mathematical induction to prove
Alex17521 [72]

Prove\ that\ the\ assumption \is \true for\ n=1\\1^3=\frac{1^2(1+1)^2}{4}\\ 1=\frac{4}{4}=1\\

Formula works when n=1

Assume the formula also works, when n=k.

Prove that the formula works, when n=k+1

1^3+2^3+3^3...+k^3+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k+1)^2}{4}+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k^2+2k+1)}{4}+(k+1)^3=\frac{(k^2+2k+1)(k^2+4k+4)}{4} \\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+4k^3+4k^2+2k^3+8k^2+8k+k^2+4k+4}{4}\\\\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+2k^3+k^2}{4}+\frac{4k^3+12k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+6k^3+13k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\

Since the formula has been proven with n=1 and n=k+1, it is true. \square

7 0
2 years ago
Cassie cleans 3 houses for $135.00. When she cleans 5 houses, she makes $225.00.. If Cassie cleans houses at a constant rate, fi
sertanlavr [38]

Answer:

45$ per house cleaned

Step-by-step explanation:

135$ / 3 houses = 45

225$/ 5 houses = 45

4 0
3 years ago
Other questions:
  • Write a number that has a zero in the tens place draw a quick picture for your number
    9·1 answer
  • What is 56/108? they are even numbers so they can be simplified but I don't know how to do it right.
    15·2 answers
  • Use a separate sheet of paper to solve the system of inequalities by graphing. Use the graph to decide if the point (1, –1) is i
    12·1 answer
  • 1. A cube has edge length 5 inches.
    13·1 answer
  • A container holds 3/4 gallon of oil. Rory is changing the oil on his vehicles and needs 6 containers. How many gallons of oil do
    13·1 answer
  • -2x^3 polynomial by degree and numbers of terms
    10·1 answer
  • !!!?? need help on this pleasee!!
    7·1 answer
  • A pet store donated a percent of every sale to charity. The total sales were ​$8,450 so the store donated ​$676 What percent of$
    15·1 answer
  • HELP WILL MARK YOU BRAINLIEST
    12·1 answer
  • What is the LCM of 8 and 10
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!