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r-ruslan [8.4K]
3 years ago
15

Im so confused all i know is that it isn't C

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

B.

Step-by-step explanation:

The answer would be B. because 2/3 as a decimal is 0.66666666...... and so on. 2/3 as a percent is 66.66666...... and so on.

2/3 is just 2 divided by 3, that gets you 0.66666.....  2/3 = 0.6666..... (decimal)

Now you know the decimal. The rule to get a percent is to move the decimal point two places to the right to get the percent.

hodyreva [135]3 years ago
3 0
Well I’m not 100 percent sure but I believe it’s b
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NEED HELP!
Pavel [41]

Answer:

588 english tst ok alright

3 0
3 years ago
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Please help ASAP I have no clue how to do this​
Salsk061 [2.6K]
It’s a triangle
s
r t

rs= 2x+10 and st= x-4

the sides are equal so equal them together then solve

2x+10=x-4
+ 4 +4
2x+14=x

you got x alone so x=2x+14

now you plug in 2x+14 in for the x in rs and st

rs= 2(2x+14)+10
4x+28+10
4x+38

st= (2x+14)-4
2x+14-4
2x-10
6 0
3 years ago
the width of a rectangle is 4 inches less than the length ,the perimeter is 48,what is the dimensions?
zalisa [80]
Answer: 10 inches × 14 inches

Work:

length = x inches
width = x - 4 inches
perimeter = 2(l+w)

48 = 2[(x)+(x - 4)]
48 = 2(2x - 4)
24 = 2x - 4
28 = 2x
14 = x

length = x inches = 14 inches
width = x - 4 inches = 14 - 4 = 10 inches
3 0
3 years ago
Read 2 more answers
Please helpppp I’m not sure how to solve
Nesterboy [21]

Answer:

If a is 1.. we substitute one in every a in g(a)

4 * 1 + 16

4+ 16 = 20

g(a)= 20

f(20)

-16 + 20 = 4

and 4/4 = 1

so f (g (a)) = a

Step-by-step explanation:

6 0
2 years ago
Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over
Darina [25.2K]

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

We have to find the expression which is equivalent to given  fraction .

\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}

Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

\frac{y-x}{x+y}

This is required expression which is equivalent to given expression.

6 0
3 years ago
Read 2 more answers
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