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Savatey [412]
3 years ago
14

Determine the mass of oxygen that is needed to react with 33 grams of phosphorus.

Chemistry
1 answer:
Kipish [7]3 years ago
8 0

Answer:

D = Mass =  42.6 g

Explanation:

Given data:

Mass of phosphorus react = 33 g

Mass of oxygen needed = ?  

Solution:

Chemical equation:

4P + 5O₂     →      2P₂O₅

Number of moles of phosphorus:

Number of moles = mass/molar mass

Number of moles = 33 g/ 30.97 g/mol

Number of moles = 1.065 mol  

now we will compare the moles of phosphorus and oxygen.  

               P         :       O₂  

               4         :        5  

        1.065        :        5/4×1.065 = 1.33mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.33 mol × 32 g/mol  

Mass = 42.6 g

Thus, 43.6 g of oxygen needed to react with 33 g of phosphorus.

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Answer:

4.5x10^{-5}\frac{kg}{L}

Explanation:

Hello!

In this case, since the density in the international system of units is given in terms of kg for the mass and L for the volume, we need to perform a process of units conversions from mg and dL to kg and L as show below:

4.5\frac{mg}d{L}*\frac{1kg}{1x10^6mg}  *\frac{10dL}{1L} \\\\4.5x10^{-5}\frac{kg}{L}

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. A sample of crude oil has a density of 0.87 g/mL. What volume (in liters) does a 3.6 kg sample of this oil occupy
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Answer:

The volume is 4.13793 L

Explanation:

Density is a quantity that expresses the relationship between the mass and the volume of a body, so it is defined as the quotient between the mass and the volume of a body:

density=\frac{mass}{volume}

Density is a characteristic property of every body or substance.

The most commonly used units of density are \frac{kg}{m^{3} } or \frac{g}{cm^{3} } for solids, and \frac{kg}{L} or \frac{g}{mL} for liquids and gases.

In this case, you know:

  • density= 0.87 \frac{g}{mL}
  • mass= 3.6 kg= 3,600 g (being 1 kg=1,000 g)
  • volume= ?

Replacing:

0.87\frac{g}{mL} =\frac{3,600 g}{volume}

Solving:

volume =\frac{3,600 g}{0.87\frac{g}{mL}}

volume= 4,137.93 mL

Being 1,000 mL=1 L, then volume= 4,137.93 mL= 4.13793 L

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