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Savatey [412]
3 years ago
14

Determine the mass of oxygen that is needed to react with 33 grams of phosphorus.

Chemistry
1 answer:
Kipish [7]3 years ago
8 0

Answer:

D = Mass =  42.6 g

Explanation:

Given data:

Mass of phosphorus react = 33 g

Mass of oxygen needed = ?  

Solution:

Chemical equation:

4P + 5O₂     →      2P₂O₅

Number of moles of phosphorus:

Number of moles = mass/molar mass

Number of moles = 33 g/ 30.97 g/mol

Number of moles = 1.065 mol  

now we will compare the moles of phosphorus and oxygen.  

               P         :       O₂  

               4         :        5  

        1.065        :        5/4×1.065 = 1.33mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.33 mol × 32 g/mol  

Mass = 42.6 g

Thus, 43.6 g of oxygen needed to react with 33 g of phosphorus.

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Alexus [3.1K]

Answer:

To calculate the amount of energy produced per gram from Uranium- 235 we call on the formula:

delta(m)= mass of the products - mass of reactants

Given the atomic mass of Xe-144 = 143.9385 amu; atomic mass of Sr-90= 89.907738 amu;  atomic mass of  U-235= 235.043922 amu

Therefore:

delta(m)=  (143.9385 + 89.907738) - (235.043922)  = -1.197682 amu

Recall that to calculate energy in joules, we use the formula:

Energy = mc^2

Therefore: Energy = (-1.197582/6.022 x 10^26)kg x (3 x 10^8 m/s)^2

= -1.7898104 x 10^-10 J

= (-1.7898104 x 10^-10 x 6.022 x 10^23/235.043922)

= -4.586 x 10^11 J per gram of  energy released

Explanation:

To calculate the amount of energy produced per gram from Uranium- 235 we call on the formula:

delta(m)= mass of the products - mass of reactants

Given the atomic mass of Xe-144 = 143.9385 amu; atomic mass of Sr-90= 89.907738 amu;  atomic mass of  U-235= 235.043922 amu

Therefore:

delta(m)=  (143.9385 + 89.907738) - (235.043922)  = -1.197682 amu

Recall that to calculate energy in joules, we use the formula:

Energy = mc^2

Therefore: Energy = (-1.197582/6.022 x 10^26)kg x (3 x 10^8 m/s)^2

= -1.7898104 x 10^-10 J

= (-1.7898104 x 10^-10 x 6.022 x 10^23/235.043922)

= -4.586 x 10^11 J per gram of  energy released

7 0
4 years ago
2. What is the limiting reagent if 0.5 g Al is reacted with 3.5 g CuCl2?(Reminder: CuCl2 is a dihydrate)
lozanna [386]

2. CuCl₂·2H₂O is limiting reactant.

Chemical reaction: 3CuCl₂·2H₂O + 2Al → 3Cu + 2AlCl₃ + 6H₂O. m(Al) = 0,5 g.

\\

8 0
3 years ago
You add 168.90 grams of NaCl to a container and then you add 616.00 grams of water to that same container What is the weight per
erma4kov [3.2K]

Answer:

The weight percent of NaCl in the container​ is 21.5%

Explanation:

Given that,

Mass of NaCl = 168.90 gram

Mass of water = 616.00 grams

We need to calculate the weight percent of NaCl in the container​

Using formula of percentage of weight

weight\ \%\  of\ component\ of\ the\ solution =\dfrac{weight\ of\ the\ component\ in\ the\ solution}{total\ weight\ of\ the\ solution}\times100

Put the value into the formula

weight\ \%\  of\ component\ of\ the\ solution =\dfrac{168.90}{168.90+616.00}\times100

weight\ \%\  of\ component\ of\ the\ solution=21.5\%

Hence, The weight percent of NaCl in the container​ is 21.5%

5 0
3 years ago
Why is specific activity used as a measurement of enzyme purity, but the turnover number cannot be used for this purpose?
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Answer:

See explanation

Explanation:

Specific activity of an enzyme is defined as a measure of the rate of reaction between enzyme and substrate.

In the study of enzyme kinetics, specific activity is particularly regarded to be the amount of substrate converted by the enzyme per milligram of protein per unit of time. It is thus a reliable measure of enzyme activity per milligram of total protein.

On the other hand, the turnover number is defined as a measure of the number of conversions achieved by a substrate molecule in one second at a particular active site depending on the specific enzyme concentration.

Since specific activityof the enzyme is the ratio of the enzyme activity to enzyme concentration, then specific activity can be used as a measurement of enzyme purity.

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Answer:

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8 0
4 years ago
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