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erastovalidia [21]
3 years ago
11

An aqueous solution is in equilibrium with a gaseous mixture containing an equal number of moles of helium, carbon dioxide, and

nitrogen. Rank the relative concentrations of each gas in the aqueous solution from highest to lowest. An aqueous solution is in equilibrium with a gaseous mixture containing an equal number of moles of helium, carbon dioxide, and nitrogen. Rank the relative concentrations of each gas in the aqueous solution from highest to lowest.
[CO2][CO2] > [He][He] > [N2][N2] [N2][N2] > [CO2][CO2] > [He][He] [CO2][CO2] > [N2][N2] > [He][He] [He][He] > [N2][N2] > [CO2][CO2]
Chemistry
1 answer:
Sophie [7]3 years ago
8 0

Answer:

[CO2] > [N2] > [He]

Explanation:

The relative concentration of CO2, N2 and He depends on the solubility of each gas in water. The more soluble in water a gas is, the greater its concentration in aqueous solution.

Among the gases listed, CO2 is most soluble in water hence it is expected to have the greatest concentration in solution followed by N2. Helium gas is insoluble in water hence it has the least concentration in the aqueous solution.

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How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is
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Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% Ba(NO_3)_2, thus,

Mass of Ba(NO_3)_2 = \frac {21.6}{100}\times 4.75\ g = 1.026 g

Molar mass of Ba(NO_3)_2 = 261.337 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.026\ g}{261.337\ g/mol}

Moles= 0.003926\ mol

Considering the reaction as:

Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3

1 moles of Ba(NO_3)_2 react with 1 mole of H_2SO_4

Thus,

0.003926 mole of Ba(NO_3)_2 react with 0.003926 mole of H_2SO_4

Moles of H_2SO_4 = 0.003926 mole

Also, considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}

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<u>So, volume = 1.7927 mL</u>

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The decomposition of NH4HS is endothermic: NH4HS(s)⇌NH3(g)+H2S(g) Part A Which change to an equilibrium mixture of this reaction
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According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

As the given reaction is as follows.

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Hence, formation of H_{2}S will decrease with decrease in volume.

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Thus, we can conclude that formation of H_{2}S will increase then.

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