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kumpel [21]
1 year ago
9

A laboratory instructor gives a sample of amino-acid powder to each of four students, I, II, III, and IV, and they weigh the sam

ples. The true value is 8.72 g. Their results for three trials are:
I: 8.72 g, 8.74 g, 8.70 g II: 8.56 g, 8.77 g, 8.83 g
III: 8.50 g, 8.48 g, 8.51 g IV: 8.41 g, 8.72 g, 8.55 g
(c) Which set of data is both the most accurate and the most precise?
Chemistry
1 answer:
Dovator [93]1 year ago
5 0

According to the calculation, set I is both the most accurate and most precise.

Exactness is a quality or state of being precise. 2a: comparison accuracy sense: the degree of precision with which an action is carried out or a measurement expressed 2b. The novel was fact-checked for historical authenticity. 2a: conformance to truth, to a standard, or to a model: exactness It is impossible to estimate the number of casualties with accuracy. Let's calculate the precision for the fourth set, consideringAV_I_V=8.56g

Δ1 = ∣(8.41−8.56)∣ g=0.15 g

Δ2 = (8.72−8.56) g=0.16 g

Δ3 = ∣(8.55−8.56)∣ g=0.01 g

Therefore: \triangle_I = \frac{\triangle1+\triangle2+\triangle3}{3} = 0.107g

Learn more about accuracy and precision here:

brainly.com/question/28289139

#SPJ4

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Help please
Mekhanik [1.2K]

Answer:

it's the regolith

hope this helps you

C Horizon - Also called regolith: the layer beneath the B Horizon and above the R Horizon. It consists of slightly broken-up bedrock. Plant roots do not penetrate into this layer; very little organic material is found in this layer. R Horizon - The unweathered rock (bedrock) layer that is beneath all the other layers.

7 0
2 years ago
What Period # is this element found in? P​
77julia77 [94]
15 is the group that phosphorus is found in.
8 0
3 years ago
Can you tell me about atoms
trasher [3.6K]

Answer:

is the smallest unit of ordinary matter that forms a chemical element.

Explanation:

and were created after the Big Bang 13.7 billion years ago.

4 0
2 years ago
Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
2 years ago
Calculate the enthalpy of combustion of 1 mol decane, C10H22, (l), to form CO2 and H2O. ∆Hf0 for decane is —300.9 kJ/mol using t
worty [1.4K]

Answer:

heyy do you got the answer? i got that cuestion but i need the answer!!! did you finally get it?

Explanation:

5 0
3 years ago
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