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kumpel [21]
1 year ago
9

A laboratory instructor gives a sample of amino-acid powder to each of four students, I, II, III, and IV, and they weigh the sam

ples. The true value is 8.72 g. Their results for three trials are:
I: 8.72 g, 8.74 g, 8.70 g II: 8.56 g, 8.77 g, 8.83 g
III: 8.50 g, 8.48 g, 8.51 g IV: 8.41 g, 8.72 g, 8.55 g
(c) Which set of data is both the most accurate and the most precise?
Chemistry
1 answer:
Dovator [93]1 year ago
5 0

According to the calculation, set I is both the most accurate and most precise.

Exactness is a quality or state of being precise. 2a: comparison accuracy sense: the degree of precision with which an action is carried out or a measurement expressed 2b. The novel was fact-checked for historical authenticity. 2a: conformance to truth, to a standard, or to a model: exactness It is impossible to estimate the number of casualties with accuracy. Let's calculate the precision for the fourth set, consideringAV_I_V=8.56g

Δ1 = ∣(8.41−8.56)∣ g=0.15 g

Δ2 = (8.72−8.56) g=0.16 g

Δ3 = ∣(8.55−8.56)∣ g=0.01 g

Therefore: \triangle_I = \frac{\triangle1+\triangle2+\triangle3}{3} = 0.107g

Learn more about accuracy and precision here:

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2. A solvent used in cleaning is found to contain only the elements carbon, hydrogen, and chlorine. When a
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mass of C = 0.238 g

mass of H =0.00989 g

mass of Cl = 1.05 g

Explanation:

Determine the masses of carbon, hydrogen, and chlorine in the original sample of the solvent.

First we need to calculate the molar mass of carbon dioxide (CO₂) and water (H₂O)

molar mass of CO₂ = molar mass of C × 1 + molar mass of O × 2

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molar mass of H₂O = molar mass of H × 2 + molar mass of O × 1

molar mass of H₂O = 1 × 2 + 16 × 1 = 18 g/mole

Now, to find the mass of carbon and hydrogen in the original sample of solvent, we devise the following reasoning:

if              44 g of CO₂ contains 12 g of C

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X = (0.872 × 12) / 44 = 0.238 g of C

if               18 g of H₂O contains 2 g of H

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Y = (0.089 × 2) / 18 = 0.00989 g of H

And now, we can find the mass of chlorine:

mass of sample = mass of C + mass of H + mass of Cl

mass of Cl = mass of sample - mass of C - mass of H

mass of Cl = 1.30 - 0.238 - 0.00989

mass of Cl = 1.05 g

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