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2 years ago

Can someone answer me this question?

Mathematics

2 answers:

photoshop1234 [79]2 years ago

8 0

Answer:

oki...whats the question?

Step-by-step explanation:

UwU

amid [387]2 years ago

4 0

Answer:

depends on the question... there is nothing attached.

Step-by-step explanation:

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What is the volume of a right circular cone that has a height of 14.9 cm and a base with the circumference of 2.9 cm rounded to

xxMikexx [17]

Answer:

The answer to your question is Volume = 3.30 cm³

Step-by-step explanation:

Data

Volume = ?

height = 14.9 cm

circumference = 2.9 cm

Process

1.- Calculate the radius

circumference = 2πr

-Substitution

2.9 = 2πr

-Solve for r

r = 2.9/2π

r = 1.45/π cm

2) Calculate the volume of the cone

Volume = 1/3πr²h

-Substitution

Volume = 1/3π(1.45/π)²(14.9)

-Simplify

Volume = (1.04)(0.213)(14.9)

Volume = 3.30 cm³

5 0

2 years ago

Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A

iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

$\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA$

7 0

2 years ago

(9x-9)(9×+9), your finding the difference between two squares. im have some trouble in how to solve it.

sergejj [24]

Answer: Your answer is 0 (F.O.I.L) first. outer. inner. last. Or you could use what my teacher calls the magic box

Step-by-step explanation:

So for the boxes you multiply for example the top left box you multiply the 9 above it and the 9 to the left or like the top right box you multiply the -9 above it and the 9 on the outside of the box to the left