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Salsk061 [2.6K]
3 years ago
15

Cole company has 298,000 shares of common stock authorized, 245,000 shares issued, and 77,000 shares of treasury stock. the comp

any's board of directors has declared a dividend of 74 cents per share. what is the total amount of the dividend that will be paid?
Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0
Last one 8000
hope helpes 
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Prove that : sin^4(2x)=3/8-1/2cos4x+1/8cos8x<br> Someone plzz help!!!
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Sin^2 (2x) = (1 - cos(4x))/2
---> sin^4 (2x) = (1/4)(1 - cos4x)^2 = (1/4)(1 - 2cos4x + cos^2 (4x)) and replace cos^2(4x) by (1/2)(1+cos(8x)) --->answer
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3 years ago
At a local preschool, there is a ratio of 3 boys to every 4 girls. If there are 245 total preschoolers enrolled, then how many a
Reika [66]

Set up the equation by writing the number of students in the ratio as a fraction:

3/4= (245-x)/x Cross multiply:

3x= 4(245-x) Multiply on right:

3x= 980-4x Add 4x on both sides:

7x= 980 Divide both sides by 7:

x= 140 this is how many girls there are. And:

245-140= 105= boys

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Writing to Explain Suppose you have a 100-mL cup, you can a 500-mL cup. List two different ways
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5 100ml cups and 1 500 ml cup


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3 years ago
In Example 3, the track has 6 lanes that are each 1 meter in width. a. What is the outer perimeter of the track? Round your answ
son4ous [18]

Answer:

Incomplete question, check attachment for the necessary diagram

Step-by-step explanation:

Note in the attachment,

We have two identical straight line of lenght

L1 = L2 = 84.39m

We also have two identical semicircle or radius 36.5m to the first track lane

But this is not the radius of the circle, the radius of the circle will now be 36.5 plus the 6 track lane and we are told that one track lane is 1m, then, the track lane is 6m

So, radius = 36.5+6

r = 42.5m

Then, we need to calculate the perimeter of the semicircle using the formula of perimeter of a circle and dividing by2

P = 2πr/2

P =πr

P = 22/7 × 42.5

P = 133.57 m

Then, the arc 1 is equal to arc 2 which is equal to 133.57 m

A1 = A2 = 133.57 m

Now we have all the dimensions,

Then, the perimeter can be calculated by adding the length of the sides

The perimeter of the field = Lenght of the two straight lines plus the length of the two semicircle arc

P = L1 + L2 + A1 + A2

P = 84.39 + 84.39 + 133.57 + 133.57

P =435.923 m

So, to the nearest meter

P ≈ 436m

The perimeter of the track is 436m

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3 years ago
6/x = x-1<br> that 6overx = x-1
Juliette [100K]
6/x = x-1

Multiply x by both sides

6= x(x-1)

Set x and x-1 equal to 6

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