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nadya68 [22]
3 years ago
8

Solve for X : 2X² + 2/5 = 12/5. *

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

X = 1

Step-by-step explanation:

Step One: 2x²+0.4 = 2.4

Step Two: 2(1)²+0.4 = 2.4

X = 1

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A container holds 23 gallon of apple juice. If four people from the cross-country track team share the juice equally, how much j
Kruka [31]

Answer:5.75

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A circle has been split into 8 sectors each of which can be colored as 4 different colors, and no consecutive sectors are colore
Eva8 [605]

Answer:

5832 ways

Step-by-step explanation:

Since the circle has 8 sectors and there is 4 colour,

Assuming the sectors are numbered 1 to 8,

Sector 1 : can be coloured with any of the 4 colour in 4 ways

Sector 2 can be coloured with any of the remaining 3 colours in 3 ways

Sector 3 in 3 ways without using the colour in sector 2

Sector 4 in 3 ways without using the colour in sector 3

Sector 5 in 3 ways without using the colour in sector 4

Sector 6 in 3 ways without using the colour in sector 5

Sector 7 in 3 ways without using the colour in sector 6

Sector 8 in 2 ways without using the colours in sector 1 and 7

Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways

3 0
3 years ago
Use the graph to answer the question.
dmitriy555 [2]

Answer:

B.

Step-by-step explanation:

hope it helps :)

3 0
3 years ago
If the area around the vegetable garden is of uniform width (labeled with x) and the dimensions of the vegetable garden is 45 fe
Nady [450]
Area of Rectangle = Width × Length

Vegetable Garden
Width = 20
Length = 45
Area of Vegetable Garden = 20×45=900 Sq ft

Area of Entire Garden = Width × Length
Width = 20 + 2x
Length = 45 + 2x
Area = (20 + 2x)(45 + 2x)
(2x + 20)(2x + 45)
4x^2 + 90x + 45x + 900
Area of Entire Garden = 4x^2 + 135x + 900

Area of Flower Garden = Area of Entire Garden - Area of Vegetable Garden

(4x^2 + 135x + 900) - (20 × 45)
4x^2 + 135x + 900 - 900
Area of Flower Garden = 4x^2 + 135x

7 0
3 years ago
A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.
AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0
3 years ago
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