Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
n=5, -5
Answer:
yes
Step-by-step explanation:
First you would find the sum of 187.56 and 49.73 which is 237.29 then you subtract this number from 18.65 which is 218.64 that's your answer
Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
To begin with, let's establish that ( x ) can equal to any number from 0 to 9.
Meaning, that ( x ) is equal to one of the following: 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.
Now that we know which values ( x ) can equal to, we will simply substitute each of the numbers as potential values of ( x ) into the six-digit number and divide it by 27 to see if it is a multiple of 27.
If X = 0
= 63X904 / 27
= 630904 / 27
= Not a whole number
Therefore, X is not equal to 0.
If X = 1
= 63X904 / 27
= 631904 / 27
= Not a whole number
Therefore, X is not equal to 1.
If X = 2
= 63X904 / 27
= 632904 / 27
= Not a whole number
Therefore, X is not equal to 2.
If X = 3
= 63X904 / 27
= 633904 / 27
= Not a whole number
Therefore, X is not equal to 3.
If X = 4
= 63X904 / 27
= 634904 / 27
= Not a whole number
Therefore, X is not equal to 4.
If X = 5
= 63X904 / 27
= 635904 / 27
= 23552
ANSWER:
Therefore, the answer is:
X = 23, 552
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