Wherever the line hits on the horizontal line on a graph.
Do you have answer choices?
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
39,000,000
Roundend to the nearest 1,000,000 or
the Millions Place.
38,802,500.0000000
Roundend to the nearest 0.0000001 or
the Ten Millionths Place.
