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Liono4ka [1.6K]
3 years ago
11

This is combine like Terms 2(3x + 7x) + 20

Mathematics
1 answer:
Semenov [28]3 years ago
3 0

Answer:

10(x + 2) here you go! hope this helps

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I need the 68th term help plz
Svet_ta [14]

Answer:

Since -14 is added in each term

Therefore,in 68 th term will be 68×-14 +(-19)

As the 1 st term is -19

68 th term= -952+(-19)

68 th term= -971

8 0
3 years ago
(z + 3)2<br> Draw me an area that shows the expression
mario62 [17]

Answer: 2z + 6

Step-by-step explanation: Distribute the 2 to z and 3.

7 0
3 years ago
20 POINTS WILL MARK AS BRAINLIEST AND SAY THANKS In 2000, the cost of many items increased because the increase in the cost of g
antoniya [11.8K]
Let the cost of gasoline in the year 2000 be represented b the equation
y = a + b*x
where
x = months, counted from January
y = cost, dollars

The given data in the table is
Month:        Jan  Feb  Mar  Apr  May  Jun  Jul  Aug  Sep  Oct  Nov  Dec
x, months:       1       2     3       4      5       6     7      8      9     10     11      12
y, dollars:     ---      ---     ---     ---   1.76   2.13   ---     ---    ---      ---    ---     ---

When x = 5, y = 1.76.
Therefore
a + 5b = 1.76               (1)

When x = 6, y = 2.13
Therefore
a + 6b = 2.13              (2)

Subtract equation (1) from (2).
a + 6b - (a + 5b) = 2.13 - 1.76
b = 0.37

From (1), obtain
a = 1.76 - 5b
   = 1.76 - 5*0.37
   = -0.09

The required equation is
y = 0.37x - 0.09
The graph shows the line, with the given data for May and June.

Answer: D.  y = 0.37x - 0.09

7 0
3 years ago
How do I solve this​
Alina [70]

\bf \qquad \qquad \textit{sum of a finite geometric sequence} \\\\ S_n=\displaystyle\sum \limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio} \end{cases} \\\\[-0.35em] ~\dotfill

\bf S_{20}=\displaystyle\sum \limits_{n=1}^{\stackrel{\stackrel{n}{\downarrow }}{20}}~\stackrel{\stackrel{a_1}{\downarrow }}{3}(\stackrel{\stackrel{r}{\downarrow }}{1.5})^{n-1}\implies S_{20}=3\left(\cfrac{1-1.5^{20}}{1-1.5} \right)\implies S_{20}=3\left(\cfrac{1-\stackrel{\approx}{3325.3}}{-0.5} \right) \\\\\\ S_{20}=3\left(\cfrac{-3324.3}{-0.5} \right)\implies S_{20}=3(6648.6)\implies S_{20}=19945.8

8 0
3 years ago
Read 2 more answers
ABCD is a isosceles trapezoid with AB=10, DB=8 and angle A=120 degrees what is the length of CD
spin [16.1K]

Answer:

The answer is 10.6 (I'm sorry if it's wrong)

Step-by-step explanation:

found out what D and B is (they both are 4 I think) then add 10 with 8 then divide 120 with 18 which is 6.6 then add what D is and then I got 10.6

5 0
3 years ago
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