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2 years ago

This is combine like Terms 2(3x + 7x) + 20

Mathematics

1 answer:

Semenov [28]2 years ago

3 0

Answer:

10(x + 2) here you go! hope this helps

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If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle?

Anastasy [175]

If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:

(x,y)=((6+2)/2, (3+1)/2)=(4,2)

Now we need to find the radius....the diameter is:

d^2=(6-2)^2+(3-1)^2

d^2=16+4

d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so

r^2=5

The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:

(h,k)=(4,2) from earlier so:

(x-4)^2+(y-2)^2=5

8 0

2 years ago

I need help please and thank you

Anit [1.1K]

Answer:

Step-by-step explanation:

The slope of the line is given. It is 4. Use the equation y=mx+b to answer the other questions.

Substitute 1 in for y, 4 in for m, and 2 in for x and solve for b. The equation would look like 1=4(2)+b.

Solving that equation will give you b=-7

That means the y-intercept is -7.

The equation would then be y=4x-7

6 0

2 years ago

Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat

SashulF [63]

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Reasoning in the same way:

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b) Now want to know when the two pools would have the same amount of water. If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

5 0

3 years ago

Simplify. Please help ASAP. I’m in a hurry.

Hoochie [10]

5 * 2 = 10
3^10/3^-2, same base, add
10 - 2 = 8
Solution: 10^8

7 0

2 years ago

What is -0.8+1.4n=2+0.7n

Sergio [31]

Answer:

n=4

Step-by-step explanation:

To solve combine your like terms.

You can start by adding 0.8 to both sides and subtracting 0.7n from both sides.

$-0.8+1.4n=2+0.7n\\1.4n=2.8+0.7n\\0.7n=2.8$

Next, divide both sides by 0.7 to isolate for n.

$0.7n=2.8\\n=4$

6 0

2 years ago