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sergeinik [125]

2 years ago

9

The queen received a diamond brooch for her birthday. The largest gem weighed 5.1 carats. There were three other gems that weigh

ed 0.7 carats, 1.4 carat, and 2.6 carats. What was the total weight of the gems?

1 answer:

lyudmila [28]2 years ago

6 0

Answer:

9.8 carats.

Step-by-step explanation:

5.1 + 0.7 + 1.4 + 2.6

= 9.8

You might be interested in

Which equation describes this line?

yawa3891 [41]

Answer:

The equation of line with given points is y - 4 = 3 ( x + 2 ) .

Step-by-step explanation:

Given as :

The points of line are ( 1 , 13 ) and ( - 2 , 4 )

The point slope intercept equation of line is

y - $y_1$ = m ( x - $x_1$ )

Where m is the slope of line

So , Slope , m = $\frac{y_2 - y_1}{x_2 - x_1}$

Or, m = $\frac{4 - 13}{ - 2 - 1}$

Or, m = $\frac{ - 9}{ - 3}$

∴ m = 3

Now The equation of line is

y - $y_1$ = m ( x - $x_1$ )

Or. y - 13 = 3 ( x - 1 )

Or, y - 13 = 3 x - 3

Or, y = 3 x - 3 + 13

∴ y = 3 x + 10

I.e y - 4 = 3 x + 6

Or, y - 4 = 3 ( x + 2 )

Hence The equation of line with given points is y - 4 = 3 ( x + 2 ) . Answer

3 0

3 years ago

21. Who is closer to Cameron? Explain.

pickupchik [31]

Problem 21

<h3>Answer: Jamie is closer</h3>

-----------------------

Explanation:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)

To find out who's closer to Cameron, we need to compute the segment lengths AC and JC. Then we pick the smaller of the two lengths.

We use the distance formula to find each length

Let's find the length of AC.

$A = (x_1,y_1) = (20,35)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from A to C} = \text{length of segment AC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-65)^2 + (35-40)^2}\\\\d = \sqrt{(-45)^2 + (-5)^2}\\\\d = \sqrt{2025 + 25}\\\\d = \sqrt{2050}\\\\d \approx 45.2769257\\\\$

The distance from Arthur to Cameron is roughly 45.2769257 units.

Let's repeat this process to find the length of segment JC

$J = (x_1,y_1) = (45,20)\\\\C = (x_2,y_2) = (65,40)\\\\d = \text{Distance from J to C} = \text{length of segment JC}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(45-65)^2 + (20-40)^2}\\\\d = \sqrt{(-20)^2 + (-20)^2}\\\\d = \sqrt{400 + 400}\\\\d = \sqrt{800}\\\\d \approx 28.2842712\\\\$

Going from Jamie to Cameron is roughly 28.2842712 units

We see that segment JC is shorter than AC. Therefore, Jamie is closer to Cameron.

=================================================

Problem 22

<h3>Answer: Arthur is closest to the ball</h3>

-----------------------

Explanation:

We have these key locations:

A = Arthur's location = (20,35)
J = Jamie's location = (45,20)
C = Cameron's location = (65,40)
B = location of the ball = (35,60)

We'll do the same thing as we did in the previous problem. This time we need to compute the following lengths:

AB
JB
CB

These segments represent the distances from a given player to the ball. Like before, the goal is to pick the smallest of these segments to find out who is the closest to the ball.

The steps are lengthy and more or less the same compared to the previous problem (just with different numbers of course). I'll show the steps on how to get the length of segment AB. I'll skip the other set of steps because there's only so much room allowed.

$A = (x_1,y_1) = (20,35)\\\\B = (x_2,y_2) = (35,60)\\\\d = \text{Distance from A to B} = \text{length of segment AB}\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(20-35)^2 + (35-60)^2}\\\\d = \sqrt{(-15)^2 + (-25)^2}\\\\d = \sqrt{225 + 625}\\\\d = \sqrt{850}\\\\d \approx 29.1547595\\\\$

Segment AB is roughly 29.1547595 units.

If you repeated these steps, then you should get these other two approximate segment lengths:

JB = 41.2310563

CB = 36.0555128

-------------

So in summary, we have these approximate segment lengths

AB = 29.1547595
JB = 41.2310563
CB = 36.0555128

Segment AB is the smallest of the trio, which therefore means Arthur is closest to the ball.

3 0

2 years ago

At the grocery store, Henry bought c pounds of cashews for $4.99 per pound. If he buys 2 pounds, how much will they cost?

Veronika [31]

The “c” pounds is a bit off putting if he only bought a pound. 2 pounds of Cashews would cost $9.98

3 0

2 years ago

Sonja bought a 14-inch pizza. How much crust is around its edge? (Use 3.14 for pi.)

Yanka [14]

The measure of the length of the edge, is given by the subsequent formula: <span>L=πD≅3.14D</span><span> where D is the diameter of your pizza, namely D= 14 inches
</span>
Answer: 3.14*14=43.96

8 0

2 years ago

Read 2 more answers

Pls pls help help help pls pls I can’t answer this it’s difficult

zhuklara [117]

Answer:

B

Step-by-step explanation:

5 0

2 years ago