If 4/9 of the hall hold 500 people, then 1/9 of the hall holds 125 people.
Times that by 9 and you have your answer which is 1125 people.
Answer:
D. 56%
Step-by-step explanation:
For the fractions we will do:

It depends on if he puts the first name back in, but I am going to asume Mr. Rosart does not, <em>so we will subtract one from the boys for the second pull</em>.
[Wanted over possible]
[Dividing] 14 / 25 = 0.56
[Making a percent] .56 * 100 = 56%
<u />
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
The best predicted weight of a person that is 156 cm is 285.4kg
<h3>We have the regression equation as </h3>
y= 106+1.15
When the adult male is 156 cm tall the weight of this person would be calculated as:
y= 106+1.15*156
y = 106 + 179.4
y = 285.4
Hence we can arrive at the conclusion that the best predicted weight of a person that is 156 cm is 285.4kg
Read more on regression equation here:
brainly.com/question/26843436
#SPJ1
Answer:
Average annual tuition is $16991 for the year 2020.
Step-by-step explanation:
By using excel for the equation of the line of best fit,
Slope of the line from given data = 380.0286
y - intercept of the line = 11290.1
Therefore, equation of the regression line will be,
y = 380.0286x + 11290.1
Where x = number of years after 2005
Now we have to calculate the average annual tuition in the year 2020,
By substituting the value of x = 2020 - 2005
= 15 years
y = 380.0286×(15) + 11290.1
y = 16990.529
≈ 16991
Therefore, average annual tuition is $16991 for the year 2020.
Answer:

Step-by-step explanation:
Given

Required
Simplify
We have:

Open brackets

Collect like terms

