To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
A few ways. you can enter it into a calculator for one, but the easiest way would be to reference a unit circle and look for an ordered pair where sin (the y value), is equal to -1/2
on a unit circle, the sin value is -1/2 at 7pi/6 and 11pi/6
because sin is the y value, it will additionally be in the quadrants III or IV based on the fact that (-1/2) as a sin value IS a negative and would have to be found in a quadrant in which sin is negative (the lower half of a coordinate plane, in this case)
The groups would meet an hour later, at 11 am.
Answer:
Step-by-step explanation:
for example
We have to write the polynomial P(x) = 5x^3 -2x^2 + 5x - 2 as a product of linear factors.
P(x) = 5x^3 -2x^2 + 5x - 2
=> P(x) = x^2( 5x - 2) + 1( 5x - 2)
=> P(x) = (x^2 + 1)(5x - 2)
There are 17 members who are only in gymnastics, 7 who are only in chess, and 3 who are in both.
17+3+7=27
800-27=773
